Prealllocation of undefined file size

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Hi, I have question. Does preallocation must be perform on a defined size? Now I have a situation that I m receiving bits from serial port. I do not know large is the file size but i will keep receiving it with this codes:
received_count=1;
file=[];
received=fgetl(s);
file=[file received];
received_count=received_count+1;
And will stored inside the file variable until I fully received the bits in a large array let say (1,M) but M is unknown values. So how do i preallocate this file to minimize the execution time?

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Walter Roberson
Walter Roberson 2011-4-27
I already answered this for you.
As that comment is now hidden in the Older Comments list, I will repeat it here:
You can preallocate to your maximum expected size, or you can dynamically allocate in chunks (e.g., 16 Kb) so as to reduce the number of allocations you need to do. To allocate in chunks, you would determine whether the new data you have would fit within the existing buffer, and if not then extend the buffer by a number of elements and then write the new data in to it. for example, file(end+16384)=0 .
  5 个评论
Walter Roberson
Walter Roberson 2011-4-27
By the way, with the dynamic allocation scheme, you should expect that there will still be a warning that the array may be growing within the loop. That's because it _is_ growing within the loop. It is not an error to grow an array within a loop: it just causes efficiency problems. The above code reduces the inefficiency.
There are dynamic allocation schemes that are more efficient than the above, that use cell arrays to assemble the data, but the code for those is more complex.
MrPuzzled Marc
MrPuzzled Marc 2011-4-28
I had tried out with the code you given to me however, error occur. How can i solve this?The data obtained from fgetl is char.
??? Error using ==> reshape
Size arguments must be real integers.
Error in ==> vlc2>Receive_Callback at 326
file(:,curpos+1:curpos+ncols) = reshape(received,16,ncols);

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