iFFT Scaling Problem
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Hi,
I want the transform a return loss versus frequency data to time domain. I have a .txt file from a cable analyzer within frequency return loss and phase information.
I wrote the ifft code. At time axis there is no problem , but the return loss values in time domain didn't match with the cable analyzer result. So i have to multiply it with a value. The code i wrote is as below:
fid = fopen('10.txt');
values= fscanf(fid,'%f %f %f \n',[3,inf]);
values = values';fclose(fid);
f = values(:,1);
rloss = values(:,2);
degree = values(:,3);
amp = 10.^(rloss/10);
radian = degree*pi/180;
complex = amp.*exp(i*radian);
GAMMA_F = complex;
%-------------IFFT-----------------------%
NFFT =517;
f1 = 700e6;
f2 = 1000e6;
Fstep = (f2-f1)/(NFFT-1);
dt = 1/(Fstep*(NFFT-1));
t = dt* [0:NFFT-1];
GAMMA_T = 30*ifft(GAMMA_F,NFFT);
RL = 10*log(abs(GAMMA_T));
In this code i have to multiply the ifft result with 30 in order to match with analyzer result. Why?
And if i change the source .txt file for a different experiment result. I have to multiply with a different factor?
I need to help to resolve this problem.
Thnaks in advance!
1 个评论
Nina Nounou
2017-3-20
hi i have the same problem as you ,can you help me please
回答（2 个）
Amit
2011-12-21
0 个投票
Hi, I too have the same problem. If you resolved it could you share your result with me. Thanks.
Wayne King
2011-12-21
It's hard to say anything definitive without knowing what is actually in this code:
rloss = values(:,2);
degree = values(:,3);
amp = 10.^(rloss/10);
I don't think this is your issue, but I doubt you want:
RL = 10*log(abs(GAMMA_T));
I suspect you minimally want
RL = 10*log10(abs(GAMMA_T));
or
RL = 20*log10(abs(Gamma_T));
2 个评论
Dr. Seis
2011-12-21
I would have suspected that the lack of symmetry (i.e., lack of negative frequencies) in the frequency domain data would have been the culprit.
Wayne King
2011-12-21
@Elige Grant that is also a very good point!
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