How to convert floating point to binary bits with the given condition?

Question

0 个投票

I have generated random numbers using rand() function.

a=rand(4,4);

out1=[0.868694705363510,0.800068480224308,0.263802916521990,0.579704587365570;

0.0844358455109103,0.431413827463545,0.145538980384717,0.549860201836332;

0.399782649098897,0.910647594429523,0.136068558708664,0.144954798223727;

0.259870402850654,0.181847028302853,0.869292207640089,0.853031117721894]

Now I want to convert thsese random numbers to binary with a condition.

Condition- If the 4th digit after the decimal point is >5, then that number should be converted to '1' else converted to '0'.

Example- let 0.868694705363510, here the 4th digit after te decimal point is 6 which is >5,

so, 0.868694705363510 should be converted to '1'.

Similarly, 0.800068480224308 , 4th digit is 0, so should be converted to '0'.

Like the above mentioned example, I want convert the out1 matrix to binary.

Help me out

Thank you

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Answer 1

Walter Roberson 2020-10-29

0 个投票

mod(a*10^4,10)>=6

Here I am taking you literally on the > 5 as not including 5 -- so it should only convert for 6, 7, 8, or 9 in that digit.

Thank you Walter, thats what I needed.