Solving equations in a for loop with changing variables

2020 10 30
1 个回答
更新时间：2020 10 31
3 次查看（30 天）

0 个投票

Hi all,
Not very experienced with matlab and trying to solve for d, L, and H as a function of x changing. The assignment asks that for the first half of x, H=0.5 and d=1.9 but I haven't been able to figure out how to start the loop in the middle of those vectors. I hardcoded a little bit to try to troubleshoot my first line, but the loop skews my depth somehow. Any advice would be greatly appreciated!

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Stephan
Stephan 2020-10-30
please insert your code - we can not copy a code from a picture...
Samantha Andeson
Samantha Andeson 2020-10-31
My apologies
x=linspace(0,50,500);
d=zeros(length(x),1);
H=zeros(length(x),1);
L=zeros(length(x),1);
%d(1:length(x)/2)=1.9;
%H(1:length(x)/2)=0.5;
H(1)=0.5; d(1)=1.9;
d(2)=d(1)-(S.*x(2)); %this is what I'm trying to make the first line
d(3)=d(2)-(S.*x(3)); %of my loop do
d(4)=d(3)-(S.*x(4));
X=x(:);
if H/d>0.8
for i=1:length(X)
d(i)=d(i)-(S.*X(i)); %1 column matrix
k(i)=getwavek(1/T,d(i)); %1 row matrix
L(i)=(2*pi)./(k(i)); %1 column matrix
n(i)=1/2.*(1+((2.*k(i).*d(i))/(sinh(2.*k(i).*d(i))))); %1 row matrix
N(i)=n(:); %Thought this would help by "index exceeds # of array elements" error
H(i)=H(i-1)./sqrt((N(i).*L(i))./(N(i-1).*L(i-1))); %This is my problem
end
end

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回答（1 个）

Juan Sagarduy
Juan Sagarduy 2020-10-30

0 个投票

Hi Samantha The first line in your code in the loop is not correct. It should d(i)=d(i-1)-S.*x(i). But then the loop must start with i=2. Otherwise, MATLAB would throw an error. Good luck / Juan

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