It follows the END that terminates the definition of the function "NumIntF" error

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Abdullah Ahmad
Abdullah Ahmad 2020-11-2
评论： Abdullah Ahmad 2020-11-2
function f =NumIntF(xi,xf)
h=0.001;
N=(xf-xi)/h;
ii=1;
while(ii<= (N+1))
if(ii==1);
x(ii)=xi;
y(ii)= cos(x(ii))*exp(sin(x(ii)))*h;
else
x(ii)=x(ii-1)+h;
y(ii)=y(ii-1)+cos(x(ii))*exp(sin(x(ii)))*h;
end
ii=ii+1;
end
f= y(N+1);
end

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采纳的回答

Alan Stevens
Alan Stevens 2020-11-2
Put
xi = 0;
xf = pi; % or whatever your desired start and end values are.
f = NumIntf(xi,xf)
in a script and run that - it worked for me.

更多回答（1 个）

Alan Stevens
Alan Stevens 2020-11-2
Just change
f=y(N+1);
to
f= y(end);

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