ODE Events Function Using Persistent Variables
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Hi all,
I am solving an ODE with an events function, which requires that it gets stopped after a certain criterion is reached in its response, which can only be determined by employing the previous values of the ODE's solution. To demonstrate that problem I have written this simple code below.
The only way I could think of achieving my above objective was by using persistent variables in the ODE events function. This allows me to keep the previous values of the solution whilst the ODE is being solved, and thus terminate it when the specific criterion is reached.
However I run into the following problem: Every time I run the script, either to debug or for any other purpose, the persistent variables are not cleared. So I have to clear them manually, and the process becomes quite tedious, and prone to error as I forget to clear all the appropriate ones some times. I have looked in to how I can clear those variables in the eventsfcn function, however I do not think that its possible to do that automatically.
Hence my question comes in two parts:
- Can I clear the persistent variables automatically before I run my code every time?
- In case not, is there a better way to achieve my above objective by not utilising persistent variables?
clear ; clc
m = 10 ;
k = 10 ;
f = 10 ;
tol = 1e-3 ;
opts = odeset('Events', @(t, y) eventfcn(t, y, tol)) ;
tspan = [0 10];
y0 = [1 0];
sol = ode15s(@(t, y) odefcn(t, y, m, k, f), tspan, y0, opts);
% Figure
figure
plot(sol.x, sol.y(2,:))
% Events Function
function [v, i, d] = eventfcn(t, y, tol)
persistent Y n
if isempty(n)
n = 0 ;
Y = 0 ;
end
n = n + 1 ;
Y(n) = y(2) ;
if numel(Y) > 2
err = diff(Y(end-1:end))/Y(end) ; % ERROR CRITERION TO STOP SOLVER
else
err = nan ;
end
if err <= tol
v = 0 ;
else
v = 1 ;
end
i = 1 ; % Halt integration
d = 0 ; % Zero can be approached from any direction
end
% ODE Function
function dydt = odefcn(t, y, m, k, f)
dydt = [y(1) ; -(k*y(2) - f)/m] ;
end
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采纳的回答
Steven Lord
2020-11-2
IMO persistent variables is not the right technique to use. One reason why is that the solver does not always evaluate your function with a time that is later than the previous evaluation. If it finds that the error estimate is not within tolerances, it may reject that time step and evaluate your function at an earlier time. So your event function may be comparing the current results against potential future results, not previous results!
What you have is more of a delay differential equation, and for that I'd use the dde23 solver or the ddesd solver. While your ddefun input would not use the "history" input Z the events function you specify in the options structure would.
4 个评论
Ameer Hamza
2020-11-3
Yes. I tried it. ODE event function is only called once a step-size is decided in the current iteration, so it will only move in the forward direction.
更多回答(1 个)
Ameer Hamza
2020-11-2
Run
clear functions
to re-initialize all the persistent variables.
2 个评论
Ameer Hamza
2020-11-3
There does seem to be some issue. Putting
clear functions
inside script does not seems to work everytime. But running it in command window works. This might be a bug.
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