How can I shift Right which is an array of numbers?

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Micky
Micky 2013-2-14
评论： vishwajit jadhav 2020-6-26
I need is a new shifted array and eventually I want to add the arrays.(New Shifted array + Original Array). Can I do something like e.g . aa =[11 22 33 44]; bb = aa(2:4); % this is shifting left It gives bb = [22 33 44], but one value is dropped out. If possible can someone provide method to shift right and how to pad the dropped out value appropriately so that the size of the new array remains same as the original array?

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Azzi Abdelmalek
Azzi Abdelmalek 2013-2-14
编辑：Azzi Abdelmalek 2013-2-14
use circshift function
circshift(aa,[0 -1])
or
circshift(aa,[0 1])
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Azzi Abdelmalek
Azzi Abdelmalek 2013-2-14
编辑：Azzi Abdelmalek 2013-2-14
n=2
x= [11;22;33;44;55;66]
x=circshift(x,[n 0])
x(1:n)=0 % or what you want

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Image Analyst
Image Analyst 2013-2-14
Not quire sure what you're describing about not dropping off any values and having bb be the same size as aa, but how about this:
aa =[11 22 33 44];
bb = zeros(size(aa))
bb(2:4) = aa(2:4)
% or
bb1 = zeros(size(aa))
bb1(1:3) = aa(2:4)
In the command window:
bb =
0 22 33 44
bb1 =
22 33 44 0
You can see there is a zero and no value is dropped off or lost and the size of bb is the same as aa. If one of those methods is not what you want, explain in more detail.
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Image Analyst
Image Analyst 2013-2-14
编辑：Image Analyst 2013-2-14
My solution will work. You just have to generalize it to "k" instead of fixed numbers of 2:4 like your example.
x = [11;22;33;44;55;66]
% k = -2;
k = +2;
s = zeros(size(x));
if k >= 1
s(k+1:end) = x(1:end-k)
elseif k <= -1
s(1:end+k) = x(-k+1:end)
end

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komal
komal 2019-6-14
Ques= x =[11;22;33;44]
i want this results
x = [0;11;22;33;44]
How can i do it:

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