Creating a matrix row by row with for loop how?

2013 2 15
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So I'm trying to figure out a way to create a matrix of x by y. Say x =[1 2 3 ] and y = [5 6 7 9 10 11]. I'm trying to get my script to shift the longest array y,to the right according to the length of x. So my matrix would look like this:
Newy =[5 6 7 8 9 10 11 0 0;
0 5 6 7 8 9 10 11 0;
0 0 5 6 7 8 9 10 11].
I know how to iterate the y array in respect to the length of x by doing :
y(mod((1:end)-i-1,end)+1)
I just can't figure out how to create a matrix row by row, I tried:
y1=[y zeros(1,length(x)-1)];
For i= 0:length(x)-1
y1(i,:) =y(mod((1:end)-i-1,end)+1);
But I keep generating errors . Any help would be much appreciated!

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Image Analyst
Image Analyst 2013-2-15

0 个投票

Try this:
x =[1 2 3 ]
y = [5 6 7 9 10 11]
ly = length(y);
y1 = zeros(length(x), max(x)+ly-1)
for row = 1 : length(x)
y1(row, x(row):x(row)+ly-1) = y;
end
y1
In the command window:
y1 =
5 6 7 9 10 11 0 0
0 5 6 7 9 10 11 0
0 0 5 6 7 9 10 11
(I hope I'm not allowing you to cheat by doing your homework for you!)

更多回答（1 个）

jessy
jessy 2013-2-15

0 个投票

Thanks a lot!i just couldn't wrap my head around it this really helped.

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