Help me with for loop

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Hi, I have matrix L with dimension 4680*640 and I need to decompose the matrix into 13 submatrix with dimension 360*640
I wrote matlab code but I got this error
" Index in position 2 exceeds array bounds (must not exceed 640). "
where n1=360 and n2=640.
My code is :
for i = 1:1:n1
for j =1:1:n2
L1(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(1*n2+1):1:(2*n2)
L2(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(2*n2+1):1:(3*n2)
L3(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(4*n2+1):1:(4*n2)
L4(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(5*n2+1):1:(5*n2)
L5(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(6*n2+1):1:(6*n2)
L6(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(7*n2+1):1:(7*n2)
L7(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(8*n2+1):1:(8*n2)
L8(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(9*n2+1):1:(9*n2)
L9(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(10*n2+1):1:(10*n2)
L10(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(11*n2+1):1:(11*n2)
L11(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(12*n2+1):1:(12*n2)
L12(i,j) = L(i,j);
end
end
for i = 1:1:n1
for j =(13*n2+1):1:(13*n2)
L13(i,j) = L(i,j);
end
end

采纳的回答

Stephen23
Stephen23 2020-11-4
编辑:Stephen23 2020-11-4
Rather than writing so much code and using numbered variables (very bad data design), you should just use mat2cell:
L = rand(4680,640); % fake data
idr = 360*ones(1,13);
idc = 640;
out = mat2cell(L,idr,idc);
size(out)
ans = 1×2
13 1
You can access the cell array contents using basic and very efficient indexing:
out{1} % the 1st matrix
out{2} % the 2nd matrix
etc.
  1 个评论
Mohammad Alwardat
Mohammad Alwardat 2020-11-4
Thanks, it's work.
I'm a beginner in MATLAB so I always write bad codes :(

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