input file - reading file

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Eddy Ramirez 2020-11-5

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评论： Mathieu NOE 2020-11-15

Greetings,

I am working on an input file that should read my txt file (test.txt) and I was testing it to see if it reads it, but it does not read the .txt file. I am getting an error when I run it, I was wondering if you guys have an ideas as to why is giving me an error. Or do you guys have another approach that I could use instead of the txt file

any help would be greatly appreciated it

%%%DATA FOR MY INPUT FILE 
10 1 %Sref bref cref
%patches
%nlattice for Patch 1
-5 0 1 -2 0 %x y z chord alphaol twist
0 0 1 -2 0 %x y z chord alphaol twist
%nlattice for Patch 1
0 0 1 -2 0 %x y z chord alphaol twist
0 0 1 -2 0 %x y z chord alphaol twist
1 10 %alpha_start alpha_step alpha_end

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Answer 1

Mathieu NOE 2020-11-5

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hello Eddy

a few minor buggs - corrected in you code

also no need to declare global variables - much more reliable to pass argument in functions

otherwise there was also a bug in your text file : the declared %Number of sections nlattice was not consistent with the actual number of lines below with data. There are only 2 lines of data while your declared 6 :

6 %Number of sections nlattice for Patch 1

5 -5 0 1 -2 0 % x y z chord alpha_0l twist %

0 0 0 1 -2 0

50 %lattice P2

6 %Number of sections nlattice for Patch 2

0 0 0 1 -2 0 % x y z chord alpha_0l twist %

5 5 0 1 -2 0

so changing the txt files + the minor bugs corrections = a solution that works !

hope it helped !

all the best , Mathieu

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Mathieu NOE 2020-11-8

在 MATLAB Online 中打开

hello Eddy

in the subfunction "exex2w.m" there are 3 lines that does not to be inside the for loop as they have any relation with the i index of the for loop

DATA.m=.5*(DATA.s+DATA.e);

DATA.c=DATA.m(:,1)+(DATA.cref/2)+DATA.m(:,2)+DATA.m(:,3);

DATA.n=(DATA.s(:,2)-DATA.e(:,2))./(DATA.s(:,2)-DATA.e(:,2));

in the 3rd line (for DATA.n) , I suspect you don't get the right dimensions because of the missing "dot" for the division ;

now , I am surprised that you have exactly the same expression on the numerator and on the denominator , so DATA.n= 1 always; please check that , is there any error in the index of the DATA used to compute DATA.n

Complete function after some minor corrections - :

function DATA=exec2w(input_files1)
%     global DATA
    
DATA=inputs_f1(input_files1);
DATA.nlatall=DATA.nlatticeP1+DATA.nlatticeP2;
DATA.alpha_step_final=DATA.alpha_start:DATA.alpha_step:DATA.alpha_end;
for i=1:DATA.nlatall/2
    DATA.s(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i-1);
   
    DATA.e(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i);
     
%     DATA.m=.5*(DATA.s+DATA.e);
%     DATA.c=DATA.m(:,1)+(DATA.cref/2)+DATA.m(:,2)+DATA.m(:,3);
%     DATA.n=(DATA.s(:,2)-DATA.e(:,2))/(DATA.s(:,2)-DATA.e(:,2));
    
end
for i=DATA.nlatall/2:DATA.nlatall
    DATA.s(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2+1);
    DATA.s(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2+1);
    DATA.s(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2+1);
    
    DATA.e(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    
%     DATA.m=.5*(DATA.s+DATA.e);
%     DATA.c=DATA.m(:,1)+(DATA.cref/2)+DATA.m(:,2)+DATA.m(:,3);
%     DATA.n=(DATA.s(:,2)-DATA.e(:,2))/(DATA.s(:,2)-DATA.e(:,2));
    
end
    DATA.m=.5*(DATA.s+DATA.e);
    DATA.c=DATA.m(:,1)+(DATA.cref/2)+DATA.m(:,2)+DATA.m(:,3);
    DATA.n=(DATA.s(:,2)-DATA.e(:,2))./(DATA.s(:,2)-DATA.e(:,2));% this equals 1 always ??
end
     
     
 

Mathieu NOE 2020-11-13

在 MATLAB Online 中打开

hello

so slight modification in the exec2w file

   DATA.test(2*i-1:2*i,:)=DATA.alpha_0l(:); % added (:) to create vertical vector in every case

this way you get the desired 6x1 output for DATA.test

I have not modified anything else

modified code below :

   function DATA=exec2w(input_files1)
    global DATA
    
DATA=inputs_f1(input_files1);
DATA.nlatall=DATA.nlatticeP1+DATA.nlatticeP2;
for i=1:DATA.nlatall/2
    DATA.s(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i-1);
   
    DATA.e(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i);
    
    DATA.ltwist=DATA.twist(1)+(DATA.twist(2)-DATA.twist(1))/(DATA.nlatall/2)*(i-1);
    % index for creating the vertical vector DATA.test
    DATA.test(2*i-1:2*i,:)=DATA.alpha_0l(:); % added (:) to create vertical vector in every case
end
keyboard
for i=DATA.nlatall/2:DATA.nlatall
    DATA.s(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    DATA.s(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    DATA.s(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    
    DATA.e(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    
    DATA.rtwist=DATA.twist1(1)+(DATA.twist1(2)-DATA.twist1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2); 
   
end
DATA.final_twist=([DATA.ltwist;DATA.rtwist]);
DATA.m=(1/2.*(DATA.s+DATA.e));
DATA.c=[(DATA.m(:,1)+(DATA.cref/2)),DATA.m(:,(2:3))];
% DATA.dihedralangle=((DATA.e(i,3)-DATA.s(i,2))/DATA.e(i,2)-DATA.s(i,2));
DATA.t=[-1,0,0];
DATA.t1=[1,0,0];
DATA.nvector=DATA.e(i,:)-DATA.s(i,:);
DATA.nvectorcross=cross(DATA.nvector,DATA.t);
DATA.nfinal=DATA.nvectorcross./norm(DATA.nvectorcross);
% DATA.cpl=((DATA.chord-DATA.chord)/(2.*DATA.nlatall));
%%For-Loop for F & Fm Matrices%%
    for irow=1:DATA.nlatall
        for jcol=1:DATA.nlatall
        DATA.bv_a=DATA.s(jcol,:)-DATA.c(irow,:);
        DATA.bv_b=DATA.e(jcol,:)-DATA.c(irow,:);
        DATA.bv_cross=cross(DATA.bv_a,DATA.bv_b);
        DATA.bv_dot=dot(DATA.bv_a,DATA.bv_b);
        DATA.bv_MagA=norm(DATA.bv_a);
        DATA.bv_MagB=norm(DATA.bv_b);
        DATA.qbv=(DATA.bv_cross./(dot(DATA.bv_cross,DATA.bv_cross))).*(DATA.bv_MagA+DATA.bv_MagB).*(1-((DATA.bv_dot)./(DATA.bv_MagA.*DATA.bv_MagB)));
        DATA.qbv_term=dot(DATA.qbv,DATA.nfinal);
        
        DATA.lhs_cross=cross(DATA.bv_a,DATA.t1);
        DATA.lhs_dot=dot(DATA.lhs_cross,DATA.lhs_cross);
        DATA.lhs_tdot=dot(DATA.bv_a,DATA.t1);
        DATA.qlhs=(DATA.lhs_cross./(dot(DATA.lhs_cross,DATA.lhs_cross))).*(1-((DATA.lhs_tdot)./(DATA.bv_MagA)));
        DATA.qlhs_term=dot(DATA.qlhs,DATA.nfinal);
        
        DATA.rhs_cross=cross(DATA.bv_b,DATA.t1);
        DATA.rhs_dot=dot(DATA.rhs_cross,DATA.rhs_cross);
        DATA.rhs_tdot=dot(DATA.bv_b,DATA.t1);
        DATA.qrhs=(DATA.rhs_cross./(dot(DATA.rhs_cross,DATA.rhs_cross))).*(1-((DATA.rhs_tdot)./(DATA.bv_MagB)));
        DATA.qrhs_term=dot(DATA.qrhs,DATA.nfinal);
        
        DATA.F=(1/(4*pi)).*(DATA.qbv_term-DATA.qlhs_term+DATA.qrhs_term);
        DATA.F_Final(irow,jcol)=DATA.F;
        
        DATA.bv_a1=DATA.s(jcol,:)-DATA.m(irow,:);
        DATA.bv_b1=DATA.e(jcol,:)-DATA.m(irow,:);
        DATA.bv_cross1=cross(DATA.bv_a1,DATA.bv_b1);
        DATA.bv_dot1=dot(DATA.bv_a1,DATA.bv_b1);
        DATA.bv_MagA1=norm(DATA.bv_a1);
        DATA.bv_MagB1=norm(DATA.bv_b1);
        DATA.qbv1=(DATA.bv_cross1./(dot(DATA.bv_cross1,DATA.bv_cross1))).*(DATA.bv_MagA1+DATA.bv_MagB1).*(1-((DATA.bv_dot1)./(DATA.bv_MagA1.*DATA.bv_MagB1)));
        DATA.qbv_term1=dot(DATA.qbv1,DATA.nfinal);
      
        DATA.lhs_cross1=cross(DATA.bv_a1,DATA.t1);
        DATA.lhs_dot1=dot(DATA.lhs_cross1,DATA.lhs_cross1);
        DATA.lhs_tdot1=dot(DATA.bv_a1,DATA.t1);
        DATA.qlhs1=(DATA.lhs_cross1./(dot(DATA.lhs_cross1,DATA.lhs_cross1))).*(1-((DATA.lhs_tdot1)./(DATA.bv_MagA1)));
        DATA.qlhs_term1=dot(DATA.qlhs1,-DATA.nfinal);
        
        DATA.rhs_cross1=cross(DATA.bv_b1,DATA.t1);
        DATA.rhs_dot1=dot(DATA.rhs_cross1,DATA.rhs_cross1);
        DATA.rhs_tdot1=dot(DATA.bv_b1,DATA.t1);
        DATA.qrhs1=(DATA.rhs_cross1./(dot(DATA.rhs_cross1,DATA.rhs_cross1))).*(1-((DATA.rhs_tdot1)./(DATA.bv_MagB1)));
        DATA.qrhs_term1=dot(DATA.qrhs1,-DATA.nfinal);
        
        DATA.Fm=(1/(4*pi)).*(DATA.qbv_term1-DATA.qlhs_term1+DATA.qrhs_term1);
        DATA.Fm_Final(irow,jcol)=DATA.Fm;   
        
        end
    end
    
%%ideas%%
for j=1:DATA.nlatall
    for AOA_w=DATA.alpha_start:DATA.alpha_step:DATA.alpha_end
    end
    DATA.alpha_0l_final=(ones(j,1).*DATA.span_char(1,5));
    keyboard
    DATA.alpha_g=asind(sind(AOA_w)*cosd(DATA.theta));
    DATA.alphag_final(j,:)=DATA.alpha_g;
    DATA.Vn_Vinf_RHS=-(sin(DATA.alphag_final+DATA.final_twist-DATA.alpha_0l_final));
    
end
end
     
     
 

Eddy Ramirez 2020-11-14

在 MATLAB Online 中打开

so is it safe to assume that it will always provide a total of 6 values for each patch because of the data that I have (based on your explanation earlier)? I guess I misunderstood and I thought that I was supposed to get only 3 rows of 1 column for DATA.alpha_0l (patch 1) and 3 rows of 1 column for DATA.alpha_0l1 (patch2) giving the following for both patches (Patch1 and Patch 2)

-2

Would I be able to run the same code for the other side? I tried to run it, for Patch2 but it is providng an error and I was trying to modify it, but not getting very lucky

%%PATCH 1 (3 lattices) 
for i=1:DATA.nlatall/2
    DATA.s(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i-1);
   
    DATA.e(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i);
    
    DATA.ltwist=DATA.twist(1)+(DATA.twist(2)-DATA.twist(1))/(DATA.nlatall/2)*(i-1);
    % index for creating the vertical vector DATA.test
    DATA.test(2*i-1:2*i,:)=DATA.alpha_0l(:); % added (:) to create vertical vector in every case
end
%%PATCH 2 (3 lattices) 
for i=DATA.nlatall/2:DATA.nlatall
    DATA.s(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    DATA.s(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    DATA.s(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    
    DATA.e(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    
    DATA.rtwist=DATA.twist1(1)+(DATA.twist1(2)-DATA.twist1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2); 
    DATA.test(2*i-1:2*i,:)=DATA.alpha_0l1(:);
end

Eddy Ramirez 2020-11-14

编辑：Eddy Ramirez 2020-11-14

在 MATLAB Online 中打开

Mathieu,

I was able to work it, I did the following

DATA.nlatall=DATA.nlatticeP1+DATA.nlatticeP2;
for i=1:DATA.nlatall/2
    DATA.s(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i-1);
    DATA.s(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i-1);
   
    DATA.e(i,1)=DATA.x(1)+(DATA.x(2)-DATA.x(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,2)=DATA.y(1)+(DATA.y(2)-DATA.y(1))/(DATA.nlatall/2)*(i);
    DATA.e(i,3)=DATA.z(1)+(DATA.z(2)-DATA.z(1))/(DATA.nlatall/2)*(i);
    DATA.F_alpha_0l(i,1)=DATA.alpha_0l(1)+(DATA.alpha_0l(2)-DATA.alpha_0l(1))/(DATA.nlatall/2)*(i);
    DATA.F_twist(i,1)=DATA.twist(1)+(DATA.twist(2)-DATA.twist(1))/(DATA.nlatall/2)*(i);
    
end
for i=DATA.nlatall/2:DATA.nlatall
    DATA.s(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    DATA.s(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    DATA.s(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2-1);
    
    DATA.e(i,1)=DATA.x1(1)+(DATA.x1(2)-DATA.x1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,2)=DATA.y1(1)+(DATA.y1(2)-DATA.y1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.e(i,3)=DATA.z1(1)+(DATA.z1(2)-DATA.z1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    
    DATA.F_alpha_0l(i,1)=DATA.alpha_0l1(1)+(DATA.alpha_0l1(2)-DATA.alpha_0l1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
    DATA.F_twist(i,1)=DATA.twist1(1)+(DATA.twist1(2)-DATA.twist1(1))/(DATA.nlatall/2)*(i-DATA.nlatall/2);
end

Eddy Ramirez 2020-11-14

do you know what the reason could be as to why my DATA.s is throwing a negative number on the third row for x?

5.0000 -5.0000 0

3.3333 -3.3333 0

-1.6667 -1.6667 0

0 0 0

1.6667 1.6667 0

3.3333 3.3333 0

Mathieu NOE 2020-11-15

hello Eddy

there is (for me) an issue with the stop index of the first for loop and the start index of the second for loop

they are both equal to DATA.nlatall/2 ( = 3) (and this shouldn't be the case normally)

at the end of the first forr loop (when i = 3) : DATA.s(i,1) = 1.6667

but then you start the second for loop again at same index i = DATA.nlatall/2 ( = 3)

so you overwrite the previous values ,

and with the new equation for DATA.s(i,1) we get a negative value : DATA.s(i,1) = -1.6667

so for me there is a problem with the index when your first for loop must stop and when your second loop must start; the index should not be the same

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