Hi @Tvoje Máma, from my understanding, you have a code that calculates “cipher” array as result. Now, you want to achieve the same result without using “for loops” in the code.
To do this, we can use Array manipulation and logical indexing functions in MATLAB that allows us to efficiently access, modify, and analyse the data within arrays.
To ensure the text fits perfectly into the matrix, we will utilize the “repmat()” function to create a string of space for padding. Next, we will use “reshape()” function to transform the padded text into matrix format. Finally, we will use “strttrim()” function to remove any leading or trailing spaces from the string. The “arrayfun()” helps to apply any function to each element of the array.
Attaching the documentation of methods used for reference:
Below is the complete MATLAB code that addresses this task:
clc; clear all; close all; echo off;
key = 'matlab';
text = 'AHOJJAJSEMTVUJSUPERPOMOCNIK';
keyNums = double(key);
[~, cisla] = sort(keyNums);
numRows = ceil(length(text) / length(key));
% Pad the text with spaces if necessary
paddedText = [text, repmat(' ', 1, numRows * length(key) - length(text))];
% Reshape the padded text into a matrix
M = reshape(paddedText, length(key), numRows)';
M_sorted = M(:, cisla);
% Convert sorted matrix to cell array of strings, also removing leading or trailing spaces with strtrim() method
cipher = arrayfun(@(col) strtrim(M_sorted(:, col)'), 1:size(M_sorted, 2), 'UniformOutput', false);
result = strjoin(strtrim(cipher), ' ');
disp(result);
I hope this helps.
