x(t) = Λ(t/4)[Π((t+4)/6)+Π((t-4)/6)]+Λ(t), t = [-10,10]

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milton 2020-11-6

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/638675-x-t-t-4-t-4-6-t-4-6-t-t-10-10

评论： milton 2020-11-11

Hi,

I am new in MatLab and I am having some trouble plotting the above x(t)using the rectpuls and i'm not sure where i am going wrong. By default the code must be like that:

step = 0.01;
t =
xt = 
figure(1)

I tried the below code but something is wrong with the tripuls's arguments.[Ihave seen that it's form is tripuls(t,w,s), where w is the width where here is 0.25? and s is the skew, where here is ...?]. In the paper I have found that: Π((t+4)/6)+Π((t-4)/6) = Π(t/6+4/6)+Π(t/6-4/6) = Π(t/(2*3)) + Π(4/6) + Π(t/(2*3) - Π(4/6) =[ Π(4/6) = 0]=u(t+3) - u(t-3) - u(t+3) + u(t-3) = 0. So finally x(t) = Λ(t), but what about the code?

step = 0.01;
t = -10:step:10;
syms t
xt = tripuls(t,0,1)*((heaviside((t+4)/6)+heaviside((t-4)/6)))+ tripuls(t);
figure(1)
fplot(t,xt);

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Debasish Samal 2020-11-10

编辑：Debasish Samal 2020-11-10

Hi,

The 'tripuls' function accepts input arguments of type 'single' or 'double' but it is 'symbolic' in this case. Can you try using these data types instead?

If you want to plot unit step function without 'Heaviside', an example can be found in the following MATLAB Answer:

https://www.mathworks.com/matlabcentral/answers/323383-plotting-a-unit-step-function-without-heaviside

-Debasish

milton 2020-11-11