Bisection method, Numerical analysis

2020 11 6
1 个回答
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更新时间：2020 11 6
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y=@(x) ((x+1)^2)*(exp(x^2-2)-1);
a=0; b=1;
m=(a+b)/2;
while abs(y(m))<0.01
disp(m)
if y(a)*y(m)<0
b=m;
elseif y(b)*y(m)<0
a=m;
end
end
~~~~~
i want to find m<0.01?
what am i doing wrong?

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 采纳的回答

Matt J
Matt J 2020-11-6
编辑：Matt J 2020-11-6
Ran in:

0 个投票

Ran in:
a=0; b=1;
m=(a+b)/2;
while abs(y(m))>0.01
if y(a)*y(m)<0
b=m;
elseif y(b)*y(m)<0
a=m;
end
m=(a+b)/2;
[m,abs(y(m))]
end
Aside from that, however, your function does not have a root in the interval [0,1], as can be seen from the following:
fplot( @(x) ((x+1)^2)*(exp(x^2-2)-1) ,[0,1]);
Warning: Function behaves unexpectedly on array inputs. To improve performance, properly vectorize your function to return an output with the same size and shape as the input arguments.

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