is there any correction..?

2 次查看(过去 30 天)
Lalit Patil
Lalit Patil 2013-2-18
I am doing Singular value decomposition using this.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
[U S V] = svd(A)
Now, i want to do the same without function. so, i written little as below.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
f = eig(A'*A);
for l = 1:length(f);
p(l) = sqrt(f(l));
end
S = diag(p);
[U,D] = eig(A*A');
[V,D] = eig(A'*A);
V = V';
U
S
But in answer i am getting only some of its elements same in matrix. And remaining are different. So, please suggest any modification if there or solution..?

回答(1 个)

Walter Roberson
Walter Roberson 2013-2-20
In your second bit of code, your S is a square diagonal matrix, not a diagonal matrix the same size as A.
  1 个评论
Lalit Patil
Lalit Patil 2013-2-20
编辑:Lalit Patil 2013-2-21
Then what change to do in S.?
And before S i want to solve problem of U and V.
What change to do in them.?

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Linear Algebra 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by