How to properly set up my Transfer function

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Jorje German
Jorje German 2020-11-7
评论： Jorje German 2020-11-12
syms s
J1 = 0.0024;
C1 = 0.007;
K12 = 2.8;
a = 0;
z = 1;
b = 1;
p = 1;
Kc = .1;
Kh = ((16000)*(1/(2*pi))*(32));
Ka = (10/32768)*2*0.1*3;
Gn = (Kh*Ka)/J1
Gd = s^2 + (C1/J1)*s + K12/J1
Cn = Kc*(a*s+z)
Cd = (b*s+p);
% Cs = Cn/Cd;
num = [Cn * Gn]
dem1 = Cd*Gd
dem2 = Cn * Gn
dem = (dem1 + dem2)
% Tf = num/(dem1 + dem2)
sys = tf(num,dem)
step(10000*sys)

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Reshma Nerella
Reshma Nerella 2020-11-10
Hi,
The numerator and denominator coefficients of transfer function should be a row vector or a cell array of row vectors. In the above of code
num = [Cn * Gn]
>> 6835652755764317/10995116277760
class(num)
>> 'sym'
You need to convert 'num' to a vector.
dem = (dem1 + dem2)
>> (s + 1)*(s^2 + (35*s)/12 + 3500/3) + 6835652755764317/10995116277760
class(dem)
>> 'sym'
Convert 'dem' to a vector of polynomial coefficients.
For example,
sys(s)=1/(2s2+3s+4);
Specify the numerator and denominator coefficients ordered in descending powers of s, and create the transfer function model.
numerator = 1;
denominator = [2,3,4];
sys = tf(numerator,denominator)
sys =
1
---------------
2 s^2 + 3 s + 4
%Continuous-time transfer function.
For more information on tf function, refer to the documentation page
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Paul
Paul 2020-11-12
zpkdata returns z and p in cell arrays; they need to be accessed as such:
>> TF=feedback(sysc*sysg,1)
TF =
621.7
------------------------------
s^3 + 2.817 s^2 + 1166 s + 505
>> [z,p,k]=zpkdata(TF);
>> z{:}
ans =
0×1 empty double column vector
>> p{:}
ans =
-1.1916 +34.1163i
-1.1916 -34.1163i
-0.4334 + 0.0000i
>> k
k =
621.6990

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