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How can generalize severel "For loop" ?

2 次查看（过去 30 天）
STamer
STamer 2013-2-20
for i=1:n
L(i,i)=1;
end
for i=2:n
L(i,1)=A(i,1)/A(1,1);
end
for i=3:n
L(i,2)=A(i,2)/A(2,2);
end
for i=4:n
L(i,3)=A(i,3)/A(3,3);
end
  2 个评论
Mark Whirdy
Mark Whirdy 2013-2-20
编辑：Mark Whirdy 2013-2-20
Hi there
What are the values of A & n?
Could you values for all variables and the required output as well as describing what you are trying to do?
José-Luis
José-Luis 2013-2-20
This is the second time in less than an hour that the same question has been asked in the forum. Looks like the instructor recommended Matlab answers. This can be done in a rather straightforward way. Please read the "Getting started" part of the documentation and ask specific questions whenever you encounter problems. People will be happy to help you then.

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采纳的回答

Sean de Wolski
Sean de Wolski 2013-2-20
Use a nested for loop:
for ii = 1:n
for jj = ii:n
stuff
end
end

更多回答（1 个）

STamer
STamer 2013-2-20
A=input('Enter nxn matrix:')
B=input('Enter solution matrix(n*1):')
[n n]=size(A);
L=zeros(n);
for i=1:n
L(i,i)=1;
end
for i=2:n
L(i,1)=A(i,1)/A(1,1);
end
for i=3:n
L(i,2)=A(i,2)/A(2,2);
end
for i=4:n
L(i,3)=A(i,3)/A(3,3);
end

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