how can i use Richardson extrapolation procedure (in explicit Euler method)
1 次查看(过去 30 天)
显示 更早的评论
function suketu
%euler exlicit method
h = 1;
x = 0:h:3;
y1 = [0];
for i = 1:length(x)-1
x(i+1)=x(i)+h;
y1(i+1) =y1(i) + h * f1(x(i), y1(i));
end
function dy = f1(x,y1)
y0 = -1;
dx=0.01;
d = 50;
c1=(y0-(d^2/(d^2+1)));
dy=c1*exp(-dx)+d*(sin(x)/(d^2+1))+d^2*(cos(x)/d^2+1);
end
0 个评论
回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Graphics Object Programming 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!