problem in converting a matrix of integers to vector of integers using str2num and num2str

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Nora Khaled
Nora Khaled 2020-11-11
评论： Nora Khaled 2020-11-12
Hello,
I have a matrix x of this form (these are example values)
1 0 0 1 0
0 1 0 0 0
0 0 0 0 1
1 0 0 1 1
I am trying to make a number out of each row so I used
y=strcat(num2str(x(:,1)),num2str(x(:,2)),num2str(x(:,3)),num2str(x(:,4)),num2str(x(:,5)));
which get me the result
'10011'
'01000'
'00001'
'10011'
Now I want to convert each string to a number but its not working.
A = str2num(y)
A =
[]
Also, I tried different method all faild beause the size of y is 4x5 and not 4x1.
why does matlab consider each char as column and how can I avoid this problem?
Thanks

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-11-11
编辑：Ameer Hamza 2020-11-11
Try this
x = [
1 0 0 1 0
0 1 0 0 0
0 0 0 0 1
1 0 0 1 1];
x = char(x+'0');
y = str2num(x)
Result
>> y
y =
10010
1000
1
10011
Or a faster solution
x = [
1 0 0 1 0
0 1 0 0 0
0 0 0 0 1
1 0 0 1 1];
y = x*10.^(size(x,2)-1:-1:0)';
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Ameer Hamza
Ameer Hamza 2020-11-11
编辑：Ameer Hamza 2020-11-11
If you want a different number of elements in each row, then string datatype is more appropriate. For example
x = [
1 0 0 1 0
0 1 0 0 0
0 0 0 0 1
1 0 0 1 1
5 0 0 90 5
5 0 0 95 0];
y = mat2cell(string(x), 6, ones(1,size(x,2)));
y = strcat(y{:});
output
>> y
y =
6×1 string array
"10010"
"01000"
"00001"
"10011"
"500905"
"500950"

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