Sorting and indexing multidimensional arrays

I would like to clarify if indexing is supported for multidimensional arrays.
For example, consider the code below.
According to the help page, the line B2 = A(I) a recover the sorted array.
However, from MATLAB Online R2020b the code snippet produces array full of ones as the result for B2.
A(:,:,1) = 1*ones(3);
A(:,:,2) = 2*ones(3);
A(:,:,3) = 3*ones(3);
A(:,:,4) = 4*ones(3);
[B,I] = sort(A,3,'descend');
B2 = A(I);

2 个评论

"According to the help page, the line B2 = A(I) a recover the sorted array."
What the sort documentation actually states is "if A is a vector, then B = A(I)" (emphasis added).
Are your data in a vector? (hint: no).
Thanks for the explanation, indeed A is not a vector. Your comment and Walter's answer have been helpful in extending the example to 3D arrays.

请先登录,再进行评论。

 采纳的回答

See https://www.mathworks.com/matlabcentral/answers/645463-help-required-for-sorting#answer_542268 -- I just happened to write up an explanation for someone of the same basic problem.
You would need to expand what I wrote there into the third dimension. You would want to change the repmat() that I show there into something more like
[ROWIDX, COLIDX] = ndgrid(1:size(A,1), 1:size(A,2));
B2 = sub2ind(size(A), ROWIDX, COLIDX, sortidx);
This is untested; you might need to use meshgrid() instead of ndgrid()

3 个评论

Thank you for the example.
The size of the inputs was slightly off in your comment but I found the below code to work after your explanation:
[ROWIDX,COLIDX,~]=ndgrid(1:size(A,1),1:size(A,2),1:size(A,3));
lix = sub2ind(size(A),ROWIDX,COLIDX,sortidx);
B2 = A(lix);
Many thanks for the help!
Edit: Change from meshgrid to ndgrid following Bruno's comment.
Thanks for the test case, Bruno!
Confirmed, thank you Bruno.

请先登录,再进行评论。

更多回答(1 个)

[B,I] = sort(A,3,'descend');
I is ndarray same size as A and B, values is 1:size(A,3) such that for any i,j
A(i,j,I(i,j,:))
is equal to
B(i,j,:)
(Both are then sorted in descending order)

类别

帮助中心File Exchange 中查找有关 Shifting and Sorting Matrices 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by