How do i reshape this matrix?

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Joseph Lister-Symonds
评论： Joseph Lister-Symonds 2020-11-13
Hello all, I'm looking for some help on the job below where I am simply trying to reshape a matrix. The data im working with is real, but i have used syms below to hopefully make it a bit easier to read.
syms a11 b11 c11 a12 b12 c12 a21 b21 c21 a22 b22 c22 a13 b13 c13 a23 b23 c23
X=[a11 b11 c11 a12 b12 c12 a13 b13 c13;
a21 b21 c21 a22 b22 c22 a23 b23 c23]
% Dimensions of new matrix M
rows=size(X,1)*size(X,2)/3
cols=3
% ----------- My attempt
for i=1:rows
for j=1:size(X,1)
for k=1:3:(size(X,2))
M(i,1:cols)=X(j,k:(k+2))
end
end
end
The result from my attempt is not what im after at all!
M =
[ a23, b23, c23]
[ a23, b23, c23]
[ a23, b23, c23]
[ a23, b23, c23]
[ a23, b23, c23]
[ a23, b23, c23]
How do I get the code to position each set of three elements (a,b,c) from X sequentially in matrix M like below?
M=[a11 b11 c11;
a12 b12 c12;
a13 b13 c13;
a21 b21 c21;
a22 b22 c22;
a23 b23 c23]

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采纳的回答

Cris LaPierre
Cris LaPierre 2020-11-13
编辑：Cris LaPierre 2020-11-13
Ran in:
I'll do it with a numeric matrix. I've replaced a,b and c with a leading 1,2 and 3.
X=[111 211 311 112 212 312 113 213 313
121 221 321 122 222 322 123 223 323];
M=reshape(X',[3,6])'
M = 6×3
111 211 311 112 212 312 113 213 313 121 221 321 122 222 322 123 223 323
●

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