How to construct and evaluate a boolean expression using symbols?
8 次查看(过去 30 天)
显示 更早的评论
If I have a boolean expression that is
y = (x1bar∨x2)(x3bar∨x4bar)(x3bar∨x5)
I am currently using a simple 1 and 0 matrix to evaluate this sometimes manually and sometimes in a for a loop. However, it is difficult to do the same for larger expressions. Is there a way that I can evaluate these expressions using symbols like the ones we have poly2sym()? In other words, using and or logical operators and the values of the variables, can I find the answer of any boolean expression without using a for a loop as my expressions should less time to evaluate compared to the other part of the code.
0 个评论
采纳的回答
Walter Roberson
2020-11-15
[X1, X2, X3, X4, X5] = ndgrid([false,true]);
X1bar = ~X1;
X3bar = ~X3;
X4bar = ~X4;
X1barvX2 = X1bar | X2;
X3barvX4bar = X3bar | X4bar;
X3barvX5 = X3bar | X5;
y = (X1barvX2) & (X3barvX4bar) & (X3barvX5);
y_table = [X1(y), X2(y), X3(y), X4(y), X5(y)];
disp(y_table)
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!