How to construct and evaluate a boolean expression using symbols?

13 次查看（过去 30 天）
Jay Vaidya
Jay Vaidya 2020-11-15
回答： Walter Roberson 2020-11-15
If I have a boolean expression that is
y = (x1bar∨x2)(x3bar∨x4bar)(x3bar∨x5)
I am currently using a simple 1 and 0 matrix to evaluate this sometimes manually and sometimes in a for a loop. However, it is difficult to do the same for larger expressions. Is there a way that I can evaluate these expressions using symbols like the ones we have poly2sym()? In other words, using and or logical operators and the values of the variables, can I find the answer of any boolean expression without using a for a loop as my expressions should less time to evaluate compared to the other part of the code.

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2020-11-15
Ran in:
[X1, X2, X3, X4, X5] = ndgrid([false,true]);
X1bar = ~X1;
X3bar = ~X3;
X4bar = ~X4;
X1barvX2 = X1bar | X2;
X3barvX4bar = X3bar | X4bar;
X3barvX5 = X3bar | X5;
y = (X1barvX2) & (X3barvX4bar) & (X3barvX5);
y_table = [X1(y), X2(y), X3(y), X4(y), X5(y)];
disp(y_table)
0 0 0 0 0 0 1 0 0 0 1 1 0 0 0 0 0 0 1 0 0 1 0 1 0 1 1 0 1 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 0 1 0 1 0 1 1 0 1 1 1 1 0 1 0 0 0 1 1 0 1 0 1 1 1 1 0 1 1

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Symbolic Math Toolbox 的更多信息

标签

产品


版本

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by