How to take logical or of all the elements in the vector without a loop?
显示 更早的评论
I am trying to use
or(a(1,1):a(1,size(a,2)))
but it doesn't run for more than 2 elements.
also when I run
or(1,1,0,0.1,0,1)
it doesn't run. It only runs for 2 inputs i.e.
or(1,0)
Is there no direct way that I can take the logical OR of elements a(1,1) to a(1,size(a,2))?
1 个评论
KSSV
2020-11-16
Is a a matrix? What exactly you are looking for?
采纳的回答
Ameer Hamza
2020-11-16
编辑：Ameer Hamza
2020-11-16
or() is an operator just defined for two inputs. In case of multiple inputs, you can use any() which is equivalent to or of all elements
>> y = any([1,1,0,0,1,0,1])
y =
logical
1
Similarly, all() is equivalent to and of all elements
>> y = all([1,1,0,0,1,0,1])
y =
logical
0
更多回答（1 个）
KSSV
2020-11-16
Note that you have two types of indexings in MATLAB.
- Indexing
This is a number and should be posittive integers greater than 0. If number is negative or fracation, it will throw error.
A = rand(1,10) ;
A(1) % first element
A(end) % last element
A(1:5) % elements from 1 to 5
A(-) % error
A(0) % error
2. Logical indexing
Here indices are 0 and 1's. This would be class of logical.
A = rand(1,10) ;
idx = A>0.5 ; % get elements greater than 0.5. 0 where conditon fails and 1 where condition mets.
A(idx) % this will pick the elements at the above condition satisfies
4 个评论
Jay Vaidya
2020-11-16
KSSV
2020-11-16
idx = a | ~a ;
Jay Vaidya
2020-11-16
编辑：Jay Vaidya
2020-11-16
KSSV
2020-11-16
a = [1 0 1 1 0 1 0 0 0 1 1 0 0 1 1 1 1 1 0 0 1] ;
b = a(1)|a(2) ;
for i = 3:length(a)
b = b|a(i) ;
end
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