why doesnt it works

2020 11 17
0 个回答
更新时间：2020 11 20
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0 个投票

for i = 1 :1: N
for j = 1 :1: N
if u(i,j) < 1-a(i,j) && N<1- (u(i,j)/(1-a(i,j)))
z= (1-a(i,j))*N
end
end
end

4 个评论
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Rik
Rik 2020-11-17
This time I edited your question for you. Next time, please use the tools explained on this page to make your question more readable.
What do you mean by 'it doesn't work'?
Peter Perkins
Peter Perkins 2020-11-19
Also, you don't need loops at all.
z = zeros(size(a));
i = (u < 1-a) && (N < 1 - u./(1-a))
z(i) = (1-a(i)) .* N;
Nirajan Khatri
Nirajan Khatri 2020-11-20
@ Rik thank you, i have u matrix and a matrix so i was trying to use conditional loop, next time i will surely do it
Nirajan Khatri
Nirajan Khatri 2020-11-20
@ Peter Perkins Sir thank you

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