Need help with factorizing array of numbers
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hi there,
say you have an array of numbers x =[94 89 124 120 150] how can i find factors of this array, i mean break each number in the array to its primes. i know the function is factor(x). but it only applies to a scalar value not an array. i tried putting it on a loop
x =[94 89 124 120 150] ;
for i = 1:length(x)
facts_x(i) = factor(x(i))
end
but this i realized gives me an error because the loop runs only in the length of x the facts_x ends up bigger because factor answer is stored as an array. please help. thanks SN
1 个评论
José-Luis
2013-2-26
Try storing it in a cell array instead:
facts_x(i) = {factor(x(i))}
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Azzi Abdelmalek
2013-2-26
编辑：Azzi Abdelmalek
2013-2-26
You need to use a cell array to store the result for each number, because they are not the same length
x =[94 89 124 120 150] ;
out=arrayfun(@factor,x,'un',0)
out{:},
5 个评论
Jan
2013-2-27
I'd prefer the explicit loop:
facts_x = cell(1, lenghth(x));
x =[94 89 124 120 150] ;
for k = 1:length(x)
facts_x{k} = factor(x(k));
end
But the result is equal. The runtime will be comparable also, because the main work happens inside factor.
Azzi Abdelmalek
2013-2-27
Please, don't add an answer as a comment , click on comment this answer and add your comment.
Azzi Abdelmalek
2013-2-27
Did you notice that your results have different sizes
The first result is [2 47]
The second result is 89
Tell how to put them in one matrix?
Jan
2013-2-27
@Azzi: Do you meant me with "don't add an asnwer as a comment"? Or did you meant the OP and "don't add a comment as an answer" instead?
I've added my code as comment, because it does exactly the same as your asnwer. Therefore this is nothing new.
Azzi Abdelmalek
2013-2-27
Jan, sorry for the confusion, I should have mentioned the name of the OP. I meant: don't add a comment as an answer.
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2013-2-26
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