How do i create an array with a for loop?

3 次查看(过去 30 天)
I'm trying to create a an array of ten numbers randomly generate from a normal distribution, and I also need the initial number to not have the same function as the remaining 9.
P_t = normrnd(72.7,7.6);
p_t = normrnd(12.6,3.9);
price = zeros(10:1);
for n = 1:10
if n == 1
price(n) = P_t;
else
price(n) = .8 * P_t + p_t;
end
end

采纳的回答

Walter Roberson
Walter Roberson 2020-11-17
编辑:Walter Roberson 2020-11-17
P_t = @() normrnd(72.7,7.6);
p_t = @() normrnd(12.6,3.9);
price = zeros(10,1);
for n = 1:10
if n == 1
price(n) = P_t();
else
price(n) = .8 * P_t() + p_t();
end
end
  2 个评论
Walter Roberson
Walter Roberson 2020-11-17
@() introduces the definition of an anonymous function that does not expect any parameters.
In the above code, each time P_t() is encountered, it would execute the function body, normrnd(72.7,7.6) , generating a new random number with the given distribution.
The code you were using was generating one single random number from each of the two distributions, and then using that same number for each iteration.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Random Number Generation 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by