How to compare two arrays?

2 次查看(过去 30 天)
Example:
aa = [1 1 1 1 -1 -1 1 1 1 1 1 1 -1 -1 1]
and
bb = [NaN NaN NaN NaN 0.2 0.3 NaN 0.2 0.3 NaN NaN NaN 0.2 0.3 NaN]
and I want to generate third array such that it contains values in bb for every value that correspond to -1 in aa, and for every other value I should get NaN, and the size of resulted should remain same as aa and bb. So the result should look something like this:
cc = [NaN NaN NaN NaN 0.2 0.3 NaN NaN NaN NaN NaN NaN 0.2 0.3 NaN].
I am doing something like this:
cc = bb(aa == -1 | isnan(bb));
But the length or the size of the array changes.
Please advice.

采纳的回答

Image Analyst
Image Analyst 2013-2-28
Try this:
cc = nan(1, length(bb))
cc(aa==-1) = bb(aa==-1)
In the command window:
cc =
NaN NaN NaN NaN 0.2000 0.3000 NaN NaN NaN NaN NaN NaN 0.2000 0.3000 NaN
  1 个评论
Micky
Micky 2013-2-28
Thank you Image analyst. Both of the responses are almost similar.

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更多回答(1 个)

Azzi Abdelmalek
Azzi Abdelmalek 2013-2-28
编辑:Azzi Abdelmalek 2013-2-28
cc=nan(1,numel(aa))
idx=find(aa==-1)
cc(idx)=bb(idx)

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