mat2cell operation coordinates cell

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Internazionale
Internazionale 2013-3-1
i have problem with cell operation. i have 2 cells, first cell is A. A has 8*8 blocks and every blocks has 8*8 pixel. the second cell is B, B has 13*13 blocks and every blocks has 8*8 pixel.
coordinates cell A (X1,Y1) and coordinates cell B (X2,Y2)
i want to process two cells to find e and f. e=X1-(0.5*X2) and f=Y1-(0.5.Y2). so finally the output, i have 169 value of e and f.
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Internazionale
Internazionale 2013-3-1
yes, for A{1,1} compare with all blocks in B cell. so for A{1,1} have 169 values of e and f
Image Analyst
Image Analyst 2013-3-2
So you have two cells. Two separate 1 element cells, not a a by 2 cell array. And the first cell is called "A" and the second cell is called "B". So, in the cell called "A" do you have a 64 row by 64 column matrix of uint8 values? Not sure how you're defining blocks and pixels, but if your array in "A" is 8 blocks tall and each block is 8 pixels tall, then that means that the whole thing is 64 pixels tall (=8*8). Am I understanding it correctly?
And B is a single cell also with one uint8 in the array, just like A, except that the uint8 array in B is 13*8 pixels tall and 13*8 pixels wide. Correct?
If so, why are you even messing with cells and not just using regular numerical arrays which are much easier to use?

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Walter Roberson
Walter Roberson 2013-3-1
编辑：Walter Roberson 2013-3-2
[X2, Y2, X1, Y1] = ndgrid(1:size(B,1), 1:size(B,2), 1:size(A,1), 1:size(A,2));
E = X1 - X2./2;
F = Y1 - Y2./2;
e = squeeze(mat2cell(E, size(B,1), size(B,2), ones(1,size(A,1)), ones(1,size(A,2))));
f = squeeze(mat2cell(F, size(B,1), size(B,2), ones(1,size(A,1)), ones(1,size(A,2))));
  2 个评论
Internazionale
Internazionale 2013-3-2
what do you mean with variable B ? matlab can not defined variable B.
Walter Roberson
Walter Roberson 2013-3-2
Your question included " the second cell is B, B has 13*13 blocks and every blocks has 8*8 pixel."
That B.

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