Info

此问题已关闭。 请重新打开它进行编辑或回答。

Error with array bounds

2 次查看(过去 30 天)
Marcelo Boldt
Marcelo Boldt 2020-11-20
关闭: MATLAB Answer Bot 2021-8-20
Dear Community,
I am creating a function and unfortunately I dont know why I am getting this error "Index in position 1 exceeds array bounds." Can you please help me?
function [ABD_dome_2] = mt_laminate(Nsection,neutral_axis,Nplies)
%% Input Material Data
%% Laminate - Aluminum 2219 T6 alloy
%Nplies = 1; %Number of plies
E = 73800; % Young's Modulus in [N/mm^2]
t2 = 4.8; % Half Thickness of the thickest segment of the tank in [mm]
t1 = 1.5; % Thickness of the thinnest segment of the tank in [mm]
t = [1.5,4.8,2];
%% Temperature Gradients - Tank + Reinforcement Cylindrical Shell
deltaT = 0;
nu = 0.33; % Poisson's ratio
Coefficient = E/(1-nu^2);
% C matrix (material coordinates)- reduced stiffness matrix
Q = Coefficient * [1,nu,0;nu,1,0;0,0,(1-nu^2)/(2*(1+nu))];
%% Classical laminar theory
T = 25; % Temperature in [°C]
a = 1;
% m = 3; To use it in case I need HIBEF
Ai = zeros(3,3);
% A = cell(Nsection,1);
% B = cell(Nsection,1);
% D = cell(Nsection,1);
Bi = zeros(3,3);
Di = zeros(3,3);
NTi = zeros(3,1);
MTi = zeros(3,1);
Qbari = zeros(3,3);
NT_plot =[];
nt_plot = zeros(3,1);
ABD = cell(Nsection,1);
for n = 1:Nsection
for m = 1:Nplies
if (t(n)/2 - neutral_axis ==0)
zbar(n) = 0 ;
A{n,:} = Ai + Q*t(n);
B{n,:} = Bi + Q * t(n) * zbar(n);
D{n,:} = Di + Q * (t(n) * zbar(n)^2 + t(n)^3 / 12);
ABD1 = {A{n,:},B{n,:};B{n,:},D{n,:}};
ABD11 = cell2mat(ABD1);
%ABD{1,:}= {A,B;B,D};
ABD{1,:} = ABD11;
else
zbar_up(n,:) = (t(n) - neutral_axis)/2;
t_up(n,:) = (t(n) - neutral_axis);
zbar_down(n,:) = (neutral_axis)/2;
t_down(n,:) = neutral_axis;
A_up{n,:} = Ai + Q * t_up(n,:);
B_up{n,:} = Bi + Q * t_up(n,:) * zbar_up(n,:);
D_up{n,:} = Di + Q * (t_up(n,:) * zbar_up(n,:)^2 + t_up(n,:)^3 / 12);
A_down{n,:} = Ai + Q * t_down(n,:);
B_down{n,:} = Bi + Q * t_down(n,:) * zbar_down(n);
D_down{n,:} = Di + Q * (t_down(n,:) * zbar_down(n,:)^2 + t_down(n,:)^3 / 12);
ABD_up{n,:} = {A_up{n,:},B_up{n,:};B_up{n,:},D_up{n,:}};
ABD_up_Matrix = cell2mat(ABD_up{n,:});
ABD_down{n,:} = {A_down{n,:},B_down{n,:};B_down{n,:},D_down{n,:}};
ABD_down_Matrix = cell2mat(ABD_down{n,:});
ABD{n,:} = ABD_up_Matrix - ABD_down_Matrix;
end
end
%% Differential System Matrix
ABD_cyl_15 = ABD{1,:};
ABD_cyl_48 = ABD{2,:};
ABD_dome_2 = ABD{3,:};
%% 1.5 mm cylindrical Segment
r_cyl = 550;
A_cyl_15 = [0, 1/r_cyl - ABD_cyl_15(1,2)/(ABD_cyl_15(1,1) *r_cyl),0,1/(ABD_cyl_15(1,1)*r_cyl),0,0,0;
1/r_cyl,0,1,0,0,0,0;
0,0,0,0,0,1/(ABD_cyl_15(4,4)*r_cyl),0;
0 , 0 , 0 , 0 , 1/r_cyl ,0,0;
0 , ABD_cyl_15(2,2)/r_cyl - ABD_cyl_15(1,2)*ABD_cyl_15(2,1)/(ABD_cyl_15(1,1)*r_cyl), 0,- (1/r_cyl) + ABD_cyl_15(2,1)/(ABD_cyl_15(1,1)*r_cyl),0,0,0.36;
0 , 0, 0, 0, -1, 0 ,0;
0,0,0,0,0,0,0];
for m = 1:90
A_15_cell{m,:} = A_cyl_15;
end
%% 4.8 mm cylindrical Segment
rho = 1100;
r_cyl = 550;
A_48_cell = cell(60,1);
A_48_cell{1,:} = zeros(7,7);
% A_cyl_48(1,1) = - ABD_cyl_48(2,1) * ABD_cyl_48(4,4) + ABD_cyl_48(2,4) * ABD_cyl_48(1,4);
%t2_a31 = - ABD_cyl_48(1,2)* ABD_cyl_48(1,4) + ABD_cyl_48(2,4)* ABD_cyl_48(1,1);
%
% t2_a41 = - ABD_cyl_48(2,1)*ABD_cyl_48(4,4)*ABD_cyl_48(1,2) + ABD_cyl_48(2,1)*ABD_cyl_48(1,4)*ABD_cyl_48(1,5) + ABD_cyl_48(2,4)*ABD_cyl_48(1,4)*ABD_cyl_48(1,2) - ABD_cyl_48(2,4)*ABD_cyl_48(1,5)*ABD_cyl_48(1,1);
% t2_a46 = - ABD_cyl_48(2,1)* ABD_cyl_48(1,4) + ABD_cyl_48(2,4)*ABD_cyl_48(1,1);
%
% det_t2 = - ABD_cyl_48(1,1)* ABD_cyl_48(4,4) + ABD_cyl_48(1,4)^2;
% A_cyl_48 = [0, 1/r_cyl - ABD_cyl_48(1,2)/(ABD_cyl_48(1,1)*r_cyl),0,1/(ABD_cyl_48(1,1)*r_cyl),0,-ABD_cyl_48(1,4)/(det_t2*r_cyl),0;
% 1/r_cyl,0,1,0,0,0,0;
% 0,-(t2_a31)/(r_cyl*det_t2),0,-ABD_cyl_48(1,4)/(r_cyl*det_t2),0,-ABD_cyl_48(1,1)/(r_cyl*det_t2),0;
% 0 , 0 , 0 , 0 , 1/r_cyl ,0,0;
% 0 , (ABD_cyl_48(2,2)/r_cyl - 1/(r_cyl*det_t2)*(t2_a41)), 0,- 1/rho + (1* t2_a11)/(r_cyl*det_t2) ,0,-((1*t2_a46)/(r_cyl*det_t2)),0.36;
% 0 , 0, 0 , 0, -1, 0,0;
% 0,0,0,0,0,0,0];
%
%
for i = 1:60
A_48_cell{i,:} =[0,1/r_cyl - ABD_cyl_48(1,2)/(ABD_cyl_48(1,1) *r_cyl),0,1/(ABD_cyl_48(1,1)*r_cyl),0,0,0;1/r_cyl,0,1,0,0,0,0;0,0,0,0,0,1/(ABD_cyl_48(4,4)*r_cyl),0;0 , 0 , 0 , 0 , 1/r_cyl ,0,0;0 , ABD_cyl_48(2,2)/r_cyl - ABD_cyl_48(1,2)*ABD_cyl_48(2,1)/(ABD_cyl_48(1,1)*r_cyl), 0,- (1/r_cyl) + ABD_cyl_48(2,1)/(ABD_cyl_48(1,1)*r_cyl),0,0,0.36;0 , 0, 0, 0, -1, 0 ,0;0,0,0,0,0,0,0];
end
end

回答(1 个)

Robert Mende
Robert Mende 2020-11-20
Would you please send the whole error message? It's problematic for anyone trying to help you find an error that might occur in any line that contains an array.
  3 个评论
Marcelo Boldt
Marcelo Boldt 2020-11-20
>> mt_laminate(3,0.75,1)
Index in position 1 exceeds array bounds.
Error in mt_laminate (line 114)
A_cyl_48 = [0, 1/r_cyl - ABD_cyl_48(1,2)/(ABD_cyl_48(1,1)
*r_cyl),0,1/(ABD_cyl_48(1,1)*r_cyl),0,0,0;1/r_cyl,0,1,0,0,0,0;0,0,0,0,0,1/(ABD_cyl_48(4,4)*r_cyl),0;0 , 0 , 0 , 0 , 1/r_cyl ,0,0;0 ,
ABD_cyl_48(2,2)/r_cyl - ABD_cyl_48(1,2)*ABD_cyl_48(2,1)/(ABD_cyl_48(1,1)*r_cyl), 0,- (1/r_cyl) +
ABD_cyl_48(2,1)/(ABD_cyl_48(1,1)*r_cyl),0,0,0.36;0 , 0, 0, 0, -1, 0 ,0;0,0,0,0,0,0,0];
Robert Mende
Robert Mende 2020-11-20
So your error appears within a part of the code that you commented out. Do you still need this part?

此问题已关闭。

产品


版本

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by