index exceeds matrix dimensions

1 次查看（过去 30 天）
Tarun Pandey
Tarun Pandey 2020-11-21
编辑： ag 2024-9-24
%consolidation for PTPB
H=10; % total depth of section
Cv=0.5; %in m^2/day
U0=100; %initial U
U1s=0;
U2s=0;
dz=1; % depth of interval
n=H/dz; %no. of depth intervals
t=40; %time in days
dt=1; %time interval
m=t/dt; %total no. of time intervals
Yw=9.81; %in KN/m2
U=zeros(n,m);
i1=input('give value of thresold gradient');
i1=fprintf('i1= %d \n',i1);
a=input('give value of a= %d');
a=fprintf('a= %4d \n',a);
alpha=input('Enter value of alpha= %5d');
alpha= fprintf('alpha = %d \n',alpha);
M=zeros(n,m);
j=0;
for l=dt:dt:39*dt
j=j+1;
for i=2:n
M(i,j)=1-(1-a)*alpha*(1-exp((-alpha/(i1*Yw)*(U(i+1,j)-U(i-1,j))/(2*dz))));
end
end

请先登录，再回答此问题。

回答（1 个）

ag
ag 2024-9-24
编辑：ag 2024-9-24
Hi Tarun,
I understand that you are encountering the "Index exceeds array bounds" error while executing the shared script. This issue occurs in the following segment of the code:
for i = 2:n
M(i, j) = 1 - (1 - a) * alpha * (1 - exp((-alpha / (i1 * Yw) * (U(i+1, j) - U(i-1, j)) / (2 * dz))));
end
The error arises because the loop iterates from `i = 2` to `n`, while the matrix `U` has a size of `n`. Therefore, attempting to access the element at the `i+1` index exceeds the array bounds.
To address this issue, you may either increase the size of the matrix `U` by 1 or adjust the loop to iterate until `n-1`, depending on what best suits your requirements.
Hope this helps!

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by