Bit wise operation of And and XOR together
2 次查看(过去 30 天)
显示 更早的评论
f10 = 1 + v2 + x2 + x2v2 + x2v3 + x3v2 + x2w2 + x2w3 + x3w2
these are the expressions and I want to perform xor and AND operation on this for 2^8 combination in binary
And if this not correct method then how can I write this expression such that it gives 1bit output as either 0 or 1 for 2^8 combination
function a=Share1(u2,v2,w2,x2,u3,v3,w3,x3)
a=bitxor(1,v2,x2,bitxor(bitand(x2,v2),bitand(x2,v3),bitand(x3,v2),bitand(x2,w2),bitand(x2,w3),bitand(x3,w2)));
end
But it is not working.
Please someone suggest how can I write this qudratic equation using MATLAB or where I am wrong
2 个评论
dpb
2020-11-21
Can you explain what the expression as written means?
Mathematically it looks like a simple sum of products of three variables [v,w,x] for two conditions.
Why then write a function with four variables [u,v,w,x] where it appears they correspond to the single/product terms and the result would just be the sum (plus the constant 1) of course?
Certainly seems no reason for bitwise operations here.
回答(2 个)
Setsuna Yuuki.
2020-11-21
The binary operation is between two values logics or values of 0's and 1's. In your code some logics operation are done between three logics values.
For example:
bitxor(bitand(x2,w2),bitand(x2,w3),bitand(x3,w2)) % bitxor(l1,l2,l3)
bitxor(bitxor(bitand(x2,w2),bitand(x2,w3)),bitand(x3,w2)) % bitxor(bitxor(l1,l2),l3)
Bruno Luong
2020-11-21
编辑:Bruno Luong
2020-11-21
Z=quad(0,1,1,0,1,0,1,1)
function F10 = quad(u2,v2,w2,x2,u3,v3,w3,x3)
% note: u2 and u3 not used anywhere
F10=1+v2+x2+x2*v2+x2*v3+x3*v2+x2*w2+x2*w3+x3*w2;
F10=mod(F10,2);
end
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!