Cell contents reference from a non-cell array object.

2020 11 22
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更新时间：2020 11 22
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clc;
clear all;
vchave = [2 2 2 2 2 2]
for k = 1:6;
v{k} = vchave
v{1,k} = v{1,k}-1
v{1}{k+1} = v{1}{k+1}-1
end
I am getting error "Cell contents reference from a non-cell array object" . Please tell me how to solve this problem.

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I am getting error "Cell contents reference from a non-cell array object" . Please tell me how to solve this problem.

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Stephen23
Stephen23 2020-11-22
编辑：Stephen23 2020-11-22
Ran in:

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Ran in:
Each cell of v contains a numeric vector. So your indexing here:
v{1}{k+1} = v{1}{k+1}-1
% ^ ^ ^ ^ wrong type of bracekts for numeric array.
uses the wrtong type of brackets for indexing (curly braces are used to access the elements of a container array, e.g. the elements of a cell array, table, or string). The correct brackets for accessing the elements of a numeric array are parentheses, as shown here:
vchave = [2,2,2,2,2,2];
for k = 1:5;
v{k} = vchave
v{1,k} = v{1,k}-1
v{1}(k+1) = v{1}(k+1)-1
end
v = 1x1 cell array
{1×6 double}
v = 1x1 cell array
{1×6 double}
v = 1x1 cell array
{1×6 double}
v = 1x2 cell array
{1×6 double} {1×6 double}
v = 1x2 cell array
{1×6 double} {1×6 double}
v = 1x2 cell array
{1×6 double} {1×6 double}
v = 1x3 cell array
{1×6 double} {1×6 double} {1×6 double}
v = 1x3 cell array
{1×6 double} {1×6 double} {1×6 double}
v = 1x3 cell array
{1×6 double} {1×6 double} {1×6 double}
v = 1x4 cell array
{1×6 double} {1×6 double} {1×6 double} {1×6 double}
v = 1x4 cell array
{1×6 double} {1×6 double} {1×6 double} {1×6 double}
v = 1x4 cell array
{1×6 double} {1×6 double} {1×6 double} {1×6 double}
v = 1x5 cell array
{1×6 double} {1×6 double} {1×6 double} {1×6 double} {1×6 double}
v = 1x5 cell array
{1×6 double} {1×6 double} {1×6 double} {1×6 double} {1×6 double}
v = 1x5 cell array
{1×6 double} {1×6 double} {1×6 double} {1×6 double} {1×6 double}
I strongly recommend preallocating v before the loop.

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