How to pick next value from vectors?

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Teemu
Teemu 2013-3-4
编辑： shariq khan 2018-12-3
I have a cumulative vector, size is about 200. I want to pick up that index where value is 0,5 or value which is next to it. For example (0.1, 0.23, 0.42, 0.49, 0.52, 0.56,...), so i want to pick up index which corresponding to value 0.52. How can I do it?
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Teemu
Teemu 2013-3-5
Minimal distance, in this case it will be 0.49

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采纳的回答

Jos (10584)
Jos (10584) 2013-3-4
Here is one approach:
v = [0.1 0.23 0.4 0.52 0.56 1.1]
idx = find(v >= 0.5,1,'first')
v(idx)
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Jan
Jan 2013-3-5
Please, Teemu, read my answer below. There you find the code to pick the element with the minimal distance. It is the 2nd line and the index is the 2nd output of min(abs(v - 0.5)).
Teemu
Teemu 2013-3-5
Sorry I didn't noticed that, I thought it was answer for next index. Thanks for your patience.

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更多回答（2 个）

Jos (10584)
Jos (10584) 2013-3-5
To do this for multiple values, take a look at my function NEARESTPOINT:
http://www.mathworks.com/matlabcentral/fileexchange/8939
Jan
Jan 2013-3-4
编辑：Jan 2013-3-5
v = [0.1 0.23 0.4 0.52 0.56 1.1];
[absdist, nearest] = min(abs(v - 0.5)); % **SOLUTION IS HERE** !!!
if absdist == 0 % or: <= eps(v(index))
following = index;
else
following = index + 1;
end
nearestValue = value(nearest);
followingValue = value(following);
  2 个评论
shariq khan
shariq khan 2018-12-3
what if I need next larger value? consider same data but my value at specific index is nil (or no value from dataset) but now I want to find if there is any value next to that specific value in the dataset
shariq khan
shariq khan 2018-12-3
编辑：shariq khan 2018-12-3
I think I found answer to my problem
Problem - all vectors are of same length
x = [some values]
t = [some values]
x1 = 0.9*max(x);
find t value that corresponds to x1 value
if not find the closest value
solution : A lot from @jan ans
[answer,index] = min(abs(x - x1))
t1(that is to be determined) = t(index);
I hope it helps to solve people facing specific problem

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