issue with imshow ploting
信息
此问题已关闭。 请重新打开它进行编辑或回答。
显示 更早的评论
I am trying to plot/show an image with the certain parameters, but it doesn't show. Only the contour. Does anyone know how I can resolve my image to be shown the the parameters and contour? Thanks in advance
imshow(image,'Border','tight','InitialMagnification',100)
colormap(gray)
hold on
contour(phi,[0 0],'r')
0 个评论
回答（2 个）
Brian B
2013-3-4
0 个投票
It is probably a scaling issue. What are the sizes of image and phi?
9 个评论
If I use
image = rand(100,140);
[X,Y] = meshgrid(1:140);
phi = cos(X/5).*sin(Y/4);
then I can see the contour on top of the image with your code.
Jerome
2013-3-4
Brian B
2013-3-4
Do you see the image after the first statement (before you change the colormap and plot the contour)?
Jerome
2013-3-4
Brian B
2013-3-4
What is the result of
min(image(:))
max(image(:))
...or just try
imshow(image,[],'Border','tight','InitialMagnification',100)
(note the empty brackets).
Jerome
2013-3-4
By default, imshow expects values between 0 and 1. You can normalize your matrix, or you can explicitly tell it what range to map to the coloraxis (using 'DisplayRange' or the bracket notation above, but with the min and max values as in [-7 255]), or you can tell it to map the whole range by passing in the empty brackets as I did above.
Jerome
2013-3-4
Image Analyst
2013-3-4
It's not clear if you meant
min(image(:)) = 7
or
min(image(:)) = -7
But either way you can do
imshow(yourImage, []);
It's also a bad idea to call your image "image" because it would blow away the built in image() function. I hope you didn't do that.
1 个评论
Brian B
2013-3-4
True! I read it so quickly I didn't even notice the missing "=".
On the same note, as a control engineer I am always appalled when examples in the MATLAB documentation assign the output of a function testing some true or false condition to a variable named tf! Where are your transfer functions, now?
此问题已关闭。
关闭：
2021-8-20
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
