ODE Function time output

Question

Carey n'eville 2020-11-23

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/659383-ode-function-time-output

评论： Carey n'eville 2020-11-24

Dear all,

I wrote the code below now, I have initial concentration 6mg/L but i need to calculate when it reaches (0.05*6) mg/L. Could you help me please? I need the t value when concentration is equal to (0.05*6) mg/L

Z0=6;
tspan = [0 24]; 
[tZ,Z] = ode45(@ConcDCE,tspan,Z0);
    function dZdt=ConcDCE(t,Z)
k1=1.26;
k2=0.74;
k3=0.22;
X0=1;
Y0=4;
Z0=6;
dZdt=k2*(Y0*exp(-k2*t)+((X0*k1)/(k2-k1)*(exp(-k1*t)-exp(-k2*t))))-k3*(Z0*exp(-k3*t)+((Y0*k2)/(k3-k2)*(exp(-k2*t)-exp(-k3*t)))+X0*k1*k2*((exp(-k1*t))/((k2-k1)*(k3-k1))-(exp(-k2*t))/((k2-k1)*(k3-k2))+(exp(-k3*t))/((k3-k1)*(k3-k2))));
    end

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Stephan 2020-11-23

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/659383-ode-function-time-output#answer_553853

编辑：Stephan 2020-11-24

在 MATLAB Online 中打开

Use events:

Z0 = 6;
Zt=0.05*6;
tspan = [0 24];
opts = odeset('Events',@(tZ,Z)EventsFcn(tZ,Z,Zt));
[tZ,Z,tZe,Ze,iZe] = ode45(@ConcDCE,tspan,Z0,opts);
plot(tZ,Z)
hold on
scatter(tZe,Ze,'or')
function dZdt=ConcDCE(t,~)
k1=1.26;
k2=0.74;
k3=0.22;
X0=1;
Y0=4;
Z0=6;
dZdt=k2*(Y0*exp(-k2*t)+((X0*k1)/(k2-k1)*(exp(-k1*t)-exp(-k2*t))))-k3*(Z0*exp(-k3*t)+((Y0*k2)/(k3-k2)*(exp(-k2*t)-exp(-k3*t)))+X0*k1*k2*((exp(-k1*t))/((k2-k1)*(k3-k1))-(exp(-k2*t))/((k2-k1)*(k3-k2))+(exp(-k3*t))/((k3-k1)*(k3-k2))));
end
    
function [Conc,isterminal,direction] = EventsFcn(~,Z,Zt)
Conc = Z - Zt; % The value that we want to be zero
isterminal = 0;  % Halt integration 
direction = 0;   % The zero can be approached from either direction
end

4 个评论
显示 2更早的评论隐藏 2更早的评论

Stephan 2020-11-24

I edited my code in my answer. For some reason I missed Z0 as initial value - accidentally I used Zt as initial value. This is corrected now. Sorry for this.

Carey n'eville 2020-11-24