How do you circshift progressive rows an increasing amount?
显示 更早的评论
If I have a matrix:
[nan nan nan nan nan]
[ 1a nan nan nan nan]
[ 1b 2b nan nan nan]
[ 1c 2c 3c nan nan]
[ 1d 2d 3d 4d nan]
I want to change it to this:
[ 1a 2b 3c 4d nan]
[ 1b 2c 3d nan nan]
[ 1c 2d nan nan nan]
[ 1d nan nan nan nan]
[nan nan nan nan nan]
I tried:
for K = 1:length(A)
A = circshift(A(:,K),K);
Thank you.
4 个评论
David Hyatt
2020-11-23
编辑：David Hyatt
2020-11-24
Rik
2020-11-23
Yes, that is indeed very slow. See my answer for a faster solution.
David Hyatt
2020-11-24
Rik
2020-11-24
I have edited my answer to include the edit I meant. Dynamically growing an array is a bad idea, as mlint is warning you. You should make it a habit of resolving every mlint warning. Either suppress them (right-click and select suppress warning on this line), or change the code.
采纳的回答
You need to index a column in A in your output as well.
for K = 1:size(A,2)
A(:,K) = circshift(A(:,K),K);
end
If you want to move every NaN to the bottom, you can also use the sort function.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
