Symbolic to double or very precise
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Hi, I have an array like this
final_lst= [ 3.926602312047918778238533343627, 7.0685827456287320885529589275467, 10.210176122813030545468205594657, 13.351768777754093124209703822879, 16.493361431346409780773598432419, 19.634954084936207731575034033848, 22.776546738526000978837700244001, 25.918139392115794217316777165947, 29.059732045705587455779451237919, 32.201324699295380694242094678508]
It is a symbolic array. I need to make it a double precision number or any number type with the most number of values after decimal places. If I use eval, then it returns only 4 places after decimal. I need as much digits after decimal as possible and I need it to be in a normal array. Could someone help ?

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Ameer Hamza
2020-11-24
Among the natively supported datatype, double() will provide most precision. You can convert a vector from symbolic to double using double()
double(final_lst)
Note that the display in command window is not same as how the number is stored in memory. For example, If you want to see more number after decimal point, you can just use
format long
double(final_lst)
2 个评论
Rik
2020-11-24
To further illustrate the point Ameer is making:
str='3.926602312047918778238533343627';
final_lst=sym(str);
fprintf('%s - sym \n',str),fprintf('%.30f - double \n',double(final_lst)),fprintf('%.30f - eps \n',eps(double(final_lst)))
另请参阅
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