Calculating Fourier Series Coefficients

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Jay Mayle
Jay Mayle 2013-3-6
回答： NIHAD 2024-11-18，5:49
I am trying to compute the trigonometric fourier series coefficients of a periodic square wave time signal that has a value of 2 from time 0 to 3 and a value of -12 from time 3 to 6. It then repeats itself. I am trying to calculate in MATLAB the fourier series coefficients of this time signal and am having trouble on where to begin.
The equation is x(t) = a0 + sum(bk*cos(2*pi*f*k*t)+ck*sin(2*pi*f*k*t))
The sum is obviously from k=1 to k=infinity.
a0, bk, and ck are the coefficients I am trying to find. Thanks for the help.
  1 个评论
omar seraj
omar seraj 2021-11-1
How to plot in Fourier series given a time interval -1.5 to 2.5I need a step by step answer to this problem please

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回答（7 个）

Rick Rosson
Rick Rosson 2013-3-6
编辑：Rick Rosson 2013-3-6
>> doc fft
>> doc real
>> doc imag
http://en.wikipedia.org/wiki/Fourier_series
Youssef Khmou
Youssef Khmou 2013-3-6
编辑：Youssef Khmou 2013-3-6
hi Jay , computing a0 bk and ck is bout theory i think, anyway try :
You have first to construct the original signal "Square(t)" so as to compare it with Fourier approximation :
clear , close all;
Fs=60;
t=0:1/Fs:20-1/Fs;
y=square(t,50);
y(y>0)=2;
y(y<0)=-12;
figure, plot(t,y);
axis ([0 20 -20 10])
% Fourier Series
a0=0;
Fy=zeros(size(t));
N=10;
for n=1:2:N
Fy=Fy+(4/n*pi)*sin(2*pi*n*t/(2*pi));
end
hold on,
plot(t,Fy,'r')
legend(' Square ','Fourier Approx');
Try now to to compute an, and bn and increase the number of iterations N and conclude
You have also to adjust the amplitudes
Kamal Kaushal
Kamal Kaushal 2020-3-1
clear , close all;
Fs=60;
t=0:1/Fs:20-1/Fs;
y=square(t,50);
y(y>0)=2;
y(y<0)=-12;
figure, plot(t,y);
axis ([0 20 -20 10])
% Fourier Series
a0=0;
Fy=zeros(size(t));
N=10;
for n=1:2:N
Fy=Fy+(4/n*pi)*sin(2*pi*n*t/(2*pi));
end
hold on,
plot(t,Fy,'r')
legend(' Square ','Fourier Approx');
Hemang Mehta
Hemang Mehta 2020-10-23
clear , close all;
Fs=60;
t=0:1/Fs:20-1/Fs;
y=square(t,50);
y(y>0)=2;
y(y<0)=-12;
figure, plot(t,y);
axis ([0 20 -20 10])
% Fourier Series
a0=0;
Fy=zeros(size(t));
N=10;
for n=1:2:N
Fy=Fy+(4/n*pi)*sin(2*pi*n*t/(2*pi));
end
hold on,
plot(t,Fy,'r')
legend(' Square ','Fourier Approx');
  2 个评论
Aaron Vargas
Aaron Vargas 2020-12-9
hello , is there any chance that you can explain to me the variables and how it works ? im stuck in a homework for college
Rik
Rik 2022-3-31
Comment posted as flag by Hariharan Hariharan:
need the flowof code for case study

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Sikha ranjith kumar
x(t)=cos(50t)
Gabriele Bunkheila
Gabriele Bunkheila 2024-7-29
编辑：Gabriele Bunkheila 2024-7-29
From a computational perspective, the Fourier Series is closely related to the Discrete Fourier Transform when talking about discrete signals (say sampled at a sampling rate fs, i.e. using a sampling period Ts = 1/fs). The Discrete Fourier Transform, in turn, is most often computed through the Fast Fourier Transform (or FFT, implemented by the fft function). That said, the Fourier Series only applies to periodic signals (say with period T).
Some of the key ideas to keep in mind when using the FFT to compute the Fourier Series include:
  • The time-domain signal segment provided as input to the fft function should include exactly an integer number of periods or the signal. The simplest case is when that's exactly 1 period made of N samples, or T = N*Ts
  • The coefficients returned by the FFT will be complex numbers. To obtain back the cosine and sine coefficients of the bk and ck coefficients, use cos and sin on the k-th complex coefficient returned by the FFT
  • The FFT will only provide a "finite" sequence of separate complex coefficients, from k=0 to k equal just below T/(2*Ts). That is N/2-1 for N even and (N-1)/2 for N odd. The actual number of complex values returned by the FFT will be up to double that number, but the second half of those can be ignored if the input time-domain sequence is real
If you need a review of the basics on this topic, I recommend taking a look at the following resources:
NIHAD
NIHAD 2024-11-18，5:49
we know that fourier series coefficients are given by and To find them just write these formulas in matlab.
your give example is 2 for t=0-3 and -12 for t=3-6. So the time period is T=6.
syms t n
assume(k>0)
assume (k,‘integer’) %assume k is a positive integer
a_0=(1/T)*(int(2,t,0,3)+int(-12,t,3,6))
a_k=(2/T)*(int(2*cos(2*k*pi*t/T),t,0,3)+int(-12*cos(2*k*pi*t/T),t,3,6))
b_k=(2/T)*(int(2*sin(2*k*pi*t/T),t,0,3)+int(-12*sin(2*k*pi*t/T),t,3,6))

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