Cant understand how the values are stored

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Rehman Tanim
Rehman Tanim 2020-11-27
评论： Rehman Tanim 2020-11-27
A = load('r08_edfm.mat');
B = load('r08_edfm.mat');
d = A.val(1,:);
d_T = d';
input_channel = 3;
noisy_sig = B.val(input_channel,:);
noisy_sig_T = noisy_sig'
at workspace im getting these values
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KSSV
KSSV 2020-11-27
What you are looking into are completely two different data sets. There is no conversion of numbers taking place.
Rehman Tanim
Rehman Tanim 2020-11-27
编辑：Image Analyst 2020-11-27
Can you please explain the data of A.val of first row? How is the data stored?

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Image Analyst
Image Analyst 2020-11-27
You forgot to attach the .mat files so we can't do much. The first row of the val matrix stored in the mat file is extracted and put into a variable you cryptically call "d". We don't know what that first row means and so we can't "explain" it. All we can tell is that the first row of val from A is stored in a row vector "d" and then you're transposing it and putting it into column vector d_T, and you're then getting the third row of the val matrix from a different mat file and calling that noise, and also transposing that row vector into a column vector called "noisy_sig_T".
Can't you ask the people who created the mat file? If you don't even know what it means, then why do you want to do anything with it? Where did you get that script, or did you write it?
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Image Analyst
Image Analyst 2020-11-27
There is no "Direct_1" column in the mat file:
A =
struct with fields:
val: [6×10000 double]
B =
struct with fields:
val: [6×10000 double]
so I'm not sure what you're talking about. And all the values in val are around 4-500 in the first part of the array, not around 42.

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