Buffer processing with high and low pass filtering ?

2 次查看（过去 30 天）
I Made
I Made 2013-3-11
I have a buffer named segmen that has < 512 x 490 int16 > values in it
r1c1 r1c2 r1c3 r1c4 r1c5 ... r1c490 (c1= column 1 r1=row 1)
r2c1 r2c2 r2c3 r2c4 r2c5 ... r2c490
.
.
.
r520c1 r2c2 r2c3 r2c4 r2c5 ... r2c490
I want to process it using formula like : (r1c1+r2c1)/2, (r1c1-r2c1)/2 -> low pass and high pass filter
i expect the output to be < 256 x 490 int 16>, but i do it wrong. Here is my code:
f=wavread('tes.wav','native');
v=[1/sqrt(2) 1/sqrt(2)]; %haar scaling function
w=[1/sqrt(2) -1/sqrt(2)]; %haar wavelet function
if mod(length(f),2)~=0
f=[f 0];
end
leftchanel=f(1:size(f),1);
segment=buffer(leftchanel,512);
d=length(segment);
m=1:d/2;
a1=segment(2*m-1).*v(1) + segment(2*m).*v(2);
d1=segment(2*m-1).*w(1) + segment(2*m).*w(2);
Using that code what i got is < 1 x 256 int 16> but i expected < 256 x 490 int 16>, i need advise to correct my mistake please ?

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Walter Roberson
Walter Roberson 2013-3-11
编辑：Walter Roberson 2013-3-11
hint:
A(2*k,:)
  2 个评论
I Made
I Made 2013-3-11
编辑：I Made 2013-3-11
it was right to do r1c1+r2c1 , but it's not looping for r1c2+r2c2... hmm i think my loop is not perfect yet, am i correct?
I Made
I Made 2013-3-11
wow thanks, i figured it out lol.
change my code into this:
a1=segment(2*m-1,:).*v(1) + segment(2*m,:).*v(2);
d1=segment(2*m-1,:).*w(1) + segment(2*m,:).*w(2);
stupid me T_T

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