Storing data in matlab matrix using loop

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MM
MM 2020-11-29
编辑： Walter Roberson 2020-11-29
Hello, I am running a loop
i=1;
for k1=2:1:20
for k2=2:1:20
for k3 = 2:1:20
M = [k1,k2,k3];
if sum(M,'all')==20
%A = M (matrix containing all three elements, k1,k2,k3) - CODE NEEDED here
end
end
end
end
I want to store all the condition abiding matrices M in matrix A, here, matrix A is the list of all the M matrices.
Thanks.

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采纳的回答

Setsuna Yuuki.
Setsuna Yuuki. 2020-11-29
编辑：Setsuna Yuuki. 2020-11-29
You can try use cell()
i=1;
for k1=2:1:20
for k2=2:1:20
for k3 = 2:1:20
M = [k1,k2,k3];
if sum(M,'all')==20
A{i} = M;
i=i+1;
end
end
end
end
A{1}
ans =
2 2 16
A{2}
ans =
2 3 15

更多回答（1 个）

Walter Roberson
Walter Roberson 2020-11-29
编辑：Walter Roberson 2020-11-29
Ran in:
[K1, K2, K3] = ndgrid(2:1:20, 2:1:20, 2:1:20);
M = K1 + K2 + K3;
mask = M == 20;
A = [K1(mask), K2(mask), K3(mask)];
size(A)
ans = 1×2
120 3
By the way: there is no point going as high as 20 in the vectors. You want a sum of 20 and the mininum value for each is 2, so the maximum that it is possible for any valid entry to be is 20 - 2 - 2 = 16, so you might as well only do 2:16

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