Unable to filter data with a for loop and replace command

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Andrew Stark
Andrew Stark 2020-12-1
回答： Walter Roberson 2020-12-1
AA=Df{1,1};
AA(AA<1|AA>1.25)=0;
BB=Zf{1,1};
for ii=1:length(AA);
if AA(ii)==0
BB(ii)=0;
end
end
AAA=replace(AA,0,[])
BBB=replace(BB,0,[])
Zf compliments Df. I am trying to filter data that is between 2 values into a new matrix and then have a matrix with the Zf component matrix that compliments the Df matrix. However, whenever I run this code it gives me the error
First argument must be a string array, character vector, or cell array of character vectors.
Error in Analyze (line 283)
AAA=replace(AA,0,[])
How can I get a filtered matrix of both?
  1 个评论
Image Analyst
Image Analyst 2020-12-1
Well it says AA is not a "string array, character vector, or cell array of character vectors" but you didn't give us AA.
What does this say? Don't use semicolons and look in the command window for answers.
AA
whos AA
Please attach Zf and Df in a mat file so we can run your code.
save('answers.mat', 'Zf', 'Df');
Then use the paper clip icon to attach answers.mat.
Or else give us code how to create those variables.

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采纳的回答

Walter Roberson
Walter Roberson 2020-12-1
replace() is a text processing function. You cannot use it to delete numeric values.
AAA = AA(AA ~= 0);
or in this particular case of comparing to 0
AAA = AA(logical(AA))

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