Flip last 3 bits of vector

Question

Jorge Zapata 2013-3-14

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/67128-flip-last-3-bits-of-vector

I have a uint16 vector which I need to flip the last 3 bits of every number.

I already have done this but I think there must be an easier solution to do this. Here is my code.

%Turn the vector to binary
V_bin = dec2bin(V,16);
for i=1:length(V)
  %Get the last 3 bits
  tmp = V_bin(14:end);
  %Convert the string to decimal
  tmpdec = bin2dec(tmp);
  %Do the flip
  tmpflip = bitcmp(uint8(tmpdec));
%Flipped to binary
tmpbin = dec2bin(tmpflip);
%Replace the flipped bits in the original string
V_bin(14:end) = tmpbin(6:end);
end
V = bin2dec(V_bin);

As you can see there are a lot of lines for a simple operation, I wonder if there is a more efficient method to do the same. Thanks

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Teja Muppirala 2013-3-14

3
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/67128-flip-last-3-bits-of-vector#answer_78580

在 MATLAB Online 中打开

You can use BITXOR,

V = uint16( round(65535*rand(5,1)) );
V2 = bitxor(V,1+2+4); % 1+2+4 = 7 = 0000000000000111
dec2bin(V)
dec2bin(V2)

2 个评论
显示无隐藏无

Jan 2013-3-14

+1, I cannot stress enough how much better this is compared to the dec2bin conversion tricks. Converting numerical data to strings for a manipulation is too indirect to be efficient.

Jorge Zapata 2013-3-14