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How can I plot a function

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Alen
Alen 2013-3-14
Hi Matlab,
I need help to plot a function.
The function is the following:
f(x) = exp(-x/8.76*10^-6)*3.83*10^-4
>> h = ezplot('exp(-x./(8.76.*10.^6)).*3,83.*10.^-4') Error using inlineeval (line 15) Error in inline expression ==> exp(-x./(8.76.*10.^6)).*3,83.*10.^-4 Error: Unexpected MATLAB expression.
Error in inline/feval (line 34) INLINE_OUT_ = inlineeval(INLINE_INPUTS_, INLINE_OBJ_.inputExpr, INLINE_OBJ_.expr);
Error in ezplotfeval (line 52) z = feval(f,x(1));
Error in ezplot>ezplot1 (line 467) [y, f, loopflag] = ezplotfeval(f, x);
Error in ezplot (line 145) [hp, cax] = ezplot1(cax, f{1}, vars, labels, args{:});
  1 个评论
Carlos
Carlos 2013-3-14
编辑：Carlos 2013-3-14
What is the x interval for your plot? From the documentation. By default ezplot(fun) plots the expression fun(x) over the default domain -2π < x < 2π, where fun(x) is an explicit function of only x.

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回答（2 个）

Walter Roberson
Walter Roberson 2013-3-18
The error is because you used comma in 3,83 instead of decimal point 3.83
Masoud Ghanbari
Masoud Ghanbari 2013-3-17
Hi
syms x
h = ezplot(exp(-x./(8.76.*10.^6)).*(3.83).*(10.^-4))

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