`integral` function: "Output of the function must be same size as input" error

13 次查看(过去 30 天)
I am trying to use the integral function in MatLab, but I get the following error depending on the anonymous function I use.
f = @(x) x;
integral(f, 1, 2) % WORKS %
ans = 1.5
% Change function
f = @(x) 1;
integral(f, 1, 2) % ERROR %
Error using integralCalc/finalInputChecks (line 526)
Output of the function must be the same size as the input. If FUN is an array-valued integrand, set the 'ArrayValued'
option to true.
What is this error, and why is it sensitive to the function I use?

采纳的回答

Walter Roberson
Walter Roberson 2020-12-1
integral() will call the given function with a vector of values, and the function must return one value for each element in the vector.
f = @(x) 1;
however, that code returns the scalar constant 1, rather than one 1 for each element of the input x. You should instead code
f = @(x) ones(size(x));
Alternately you can code
integral(f, 1, 2, 'arrayvalued', true)
but that can be slower as it forces integral() to not use vectorized calls.
  3 个评论
Walter Roberson
Walter Roberson 2020-12-1
It isn't just "like" using vector ops to speed things up, it is using that.
For scalar-valued problems, the function y = fun(x) must accept a vector argument, x, and return a vector result, y. This generally means that fun must use array operators instead of matrix operators. For example, use .* (times) rather than * (mtimes). If you set the 'ArrayValued' option to true, then fun must accept a scalar and return an array of fixed size.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Programming 的更多信息

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by