Elegant / Vectorized way of getting array from start_index vector and end_index vector?

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Evan
Evan 2013-3-16
Hello
Suppose start_index = [1 5 10]; and end_index = [3 8 12];
Is there an elegant solution to get an output of [1 2 3 5 6 7 8 10 11 12], that is the function takes each start value and gives all inclusive values between the start and end value, repeats with the next index, until all inclusive values are included in a single output vector?
Thank you

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Azzi Abdelmalek
Azzi Abdelmalek 2013-3-16
编辑：Azzi Abdelmalek 2013-3-16
EDIT
v=[1 2 3 5 6 7 8 10 11 12]
start_index = [1 5 10];
end_index = [3 8 12];
out=cell2mat(arrayfun(@(x,y) x:y,start_index, end_index,'un',0))
out=intersect(out,v)

更多回答（1 个）

Jan
Jan 2013-3-16
编辑：Jan 2013-3-16
start_index = [1 5 10];
end_index = [3 8 12];
index(end_index + 1) = -1; % Implicit pre-allocation
index(start_index) = 1;
result = find(cumsum(index));
In many cases logical indexing is more efficient:
result = (cumsum(index(1:end-1)) == 1);
An even more efficient method is FEX: mcolon.

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