least significant bit process

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Internazionale
Internazionale 2013-3-17
i have matrix A, let we say, A=rand(1,256). A contains important coefficient. Because A is decimal like 0.xxxx, so i make B=A*10000. i make this for i can process dec2bin because i don't know how to convert decimal number to biner. after i get B, C=dec2bin(B,18).
i got 256 binary value of C. i want process LSB every value of C, every bits in c(1,1) until C(1,256) @18 bits must change the least significant bit of F.
example, C(1,1) = 001101010101010111 embedded into least bits of F, from F(1,1) until F(1,18) and until the whole C
A=rand(1,256);
B=A*10000;
C=dec2bin(B,18);
D=rand(1,5000);
E=F*10000;
F=dec2bin(E,18);

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回答（1 个）

Walter Roberson
Walter Roberson 2013-3-17
B = fix(A * 10000);
lsb = mod(B,2);
changed_B = B - lsb + newlsb;
where newlsb is the values (0 or 1) of the new bits.
  2 个评论
Internazionale
Internazionale 2013-3-17
sir, i think you're wrong with my question. read my example.
Walter Roberson
Walter Roberson 2013-3-17
B is not going to have 18 bits worth of integer information per location. The maximum value for any B entry is going to be 1 * 10000, and that will have about 13.28771238 bits of integer information.

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