Reinforcement Learning Noise Model Mean Attraction Constant

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What does the mean attraction constant do? How can I tune it properly to promote exploration and learning? I can't seem to get the logic behind it.
With a sample time of 2, when I set it to 1 I get very noisy outputs. In the following graphs, rpm and valve%opening are the agents outputs and they are already scaled by a scaling layer.
When I set it to 0.05, then it seems like the noise model is not doing much explorations.
I also noticed that by applying the abs(1 - MeanAttractionConstant.*SampleTime) formula,
When sample time is 2 and the MAC is 1, the formula gives 1.
When sample time is 2 and the MAC is 0.05, the formula gives 0.9.
How does this relate to how fast the noise converge to the mean?
Thank you very much.

采纳的回答

Emmanouil Tzorakoleftherakis
Assuming you are using DDPG, there is some information on the noise model here. I wouldn't worry too much about the mean attraction constant. The value of variance, variancedecayrate and variancemin play a much bigger role on 1) how much noise is added to the agent output and 2) for how long. If you want less noise to be added, reduce the variance value. If you want to explore for longer time, reduce the decay rate and set variancemin to a larger value.
  4 个评论
Tech Logg Ding
Tech Logg Ding 2020-12-6
Hi Emmanouil,
Hi, I tried that and tweaked the training hyper parameters a little to arrive at an suboptimal solution!
Thank you very much for your help!
Sourabh
Sourabh 2024-1-9
i am using DDPG and i need to set my sample time to 800 sec and then i got error as
abs(1 - mean attrc const.*sample time) <= 1
so i made mean att cont.(mac) to 0.0001 but still i am getting the same error
my question is i have to change the mac in noise options of agent or is it some different mean attarc const.

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