How to plot the opposite direction field
2 次查看(过去 30 天)
显示 更早的评论
I have this code written for the flow field. But I want the opposite to happen, the image below should be inside out. The longest direction lines should be on the inside and the outside should have the smallest direction lines. It should be inside out, if that makes sense
%Define parameters for the velocity profile
w=2*pi; %rad/s
R=15; %cm
%Create a meshgrid of cylindrical coordinates
[r,theta]=meshgrid(R:R/10:0,2*pi:pi/12:0);
%Define the Cartesian coordinates
x=r.*cos(theta);
y=r.*sin(theta);
%Calculate the linear velocity components in cartesian coordinates
u=-w.*r.*sin(theta);
v=w.*r.*cos(theta);
%Create a 2d vector plot of the velocity
quiver(x,y,u,v);
daspect([1 1 1]);
xlabel('x, cm');
ylabel('y, cm');
title('Title')
%Define the axis ranges
axis([-R R -R R]);
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/451358/image.png)
0 个评论
采纳的回答
Ameer Hamza
2020-12-7
Try this
quiver(x, y, 1./u, 1./v);
2 个评论
Ameer Hamza
2020-12-7
编辑:Ameer Hamza
2020-12-7
The suggestion about meshgrid was given by VBBV. I only suggested to modify quiver() line. Anyway, try the following code
%Define parameters for the velocity profile
w=2*pi; %rad/s
R=15; %cm
%Create a meshgrid of cylindrical coordinates
[r,theta]=meshgrid(R/10:R/10:R,0:pi/10:2*pi);
%Define the Cartesian coordinates
x=r.*cos(theta);
y=r.*sin(theta);
%Calculate the linear velocity components in cartesian coordinates
u=-w.*1./r.^(1/2).*sin(theta);
v=w.*1./r.^(1/2).*cos(theta);
%Create a 2d vector plot of the velocity
quiver(x,y,u,v);
daspect([1 1 1]);
xlabel('x, cm');
ylabel('y, cm');
title('Title')
%Define the axis ranges
axis([-R R -R R]);
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/451518/image.png)
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Vector Fields 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!