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How to plot the opposite direction field

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EA
EA 2020-12-7
编辑： Ameer Hamza 2020-12-7
I have this code written for the flow field. But I want the opposite to happen, the image below should be inside out. The longest direction lines should be on the inside and the outside should have the smallest direction lines. It should be inside out, if that makes sense
%Define parameters for the velocity profile
w=2*pi; %rad/s
R=15; %cm
%Create a meshgrid of cylindrical coordinates
[r,theta]=meshgrid(R:R/10:0,2*pi:pi/12:0);
%Define the Cartesian coordinates
x=r.*cos(theta);
y=r.*sin(theta);
%Calculate the linear velocity components in cartesian coordinates
u=-w.*r.*sin(theta);
v=w.*r.*cos(theta);
%Create a 2d vector plot of the velocity
quiver(x,y,u,v);
daspect([1 1 1]);
xlabel('x, cm');
ylabel('y, cm');
title('Title')
%Define the axis ranges
axis([-R R -R R]);

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-12-7
Try this
quiver(x, y, 1./u, 1./v);
  2 个评论
EA
EA 2020-12-7
That does not work. The meshgrid comes out blank
Ameer Hamza
Ameer Hamza 2020-12-7
编辑：Ameer Hamza 2020-12-7
The suggestion about meshgrid was given by VBBV. I only suggested to modify quiver() line. Anyway, try the following code
%Define parameters for the velocity profile
w=2*pi; %rad/s
R=15; %cm
%Create a meshgrid of cylindrical coordinates
[r,theta]=meshgrid(R/10:R/10:R,0:pi/10:2*pi);
%Define the Cartesian coordinates
x=r.*cos(theta);
y=r.*sin(theta);
%Calculate the linear velocity components in cartesian coordinates
u=-w.*1./r.^(1/2).*sin(theta);
v=w.*1./r.^(1/2).*cos(theta);
%Create a 2d vector plot of the velocity
quiver(x,y,u,v);
daspect([1 1 1]);
xlabel('x, cm');
ylabel('y, cm');
title('Title')
%Define the axis ranges
axis([-R R -R R]);

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